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3 years ago

Find the domain and range, graph

Mathematics

1 answer:

borishaifa [10]3 years ago

3 0

Answer:

Step-by-step explanation:

An way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

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How to find z statistic for test?

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2 years ago

Put in least to highest order 6.86,6.8,7,6.9,6.827 and 12.03,1.2,12.3,1.203,12.301

Anon25 [30]

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2 years ago

Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95

Virty [35]

Answer:

$L(x)=1+\dfrac{1}{3}x$

$\sqrt[3]{0.95} \approx 0.9833$

$\sqrt[3]{1.1} \approx 1.0333$

Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial, $L(x)=f(a)+f'(a)(x-a)$

a=0

$g(0)=\sqrt[3]{1+0}=1$

$g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}$

Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

(b) $\sqrt[3]{0.95}= \sqrt[3]{1-0.05}$

When x = - 0.05

$L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833$

$\sqrt[3]{0.95} \approx 0.9833$

(c)

(b) $\sqrt[3]{1.1}= \sqrt[3]{1+0.1}$

When x = 0.1

$L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333$

$\sqrt[3]{1.1} \approx 1.0333$

7 0

3 years ago

I need help with premetier and area for 7 8 9

SCORPION-xisa [38]

The answers to the three shapes are:

Figure 7; perimeter = 16.2mm, area = 12.64 square mm

Figure 8; perimeter = 15.2inches, area = 9.61 square inches

Figure 9; perimeter = 21.47yards, area = 16.81 square yards

<h3>What is the perimeter of a shape?</h3>

Perimeter is the outside boundary of a plane shape.

Analysis:

for figure 7, perimeter = s + s + s = 3s = 3(5.4) = 16.2mm

Height of triangle = $\sqrt{((5.4)^{2} - (2.7)^{2} }$ = 4.68

Area of triangle = 1/2 base x height = 1/2 x 5.4 x 4.68 = 12.64 $mm^{2}$

For figure 8, perimeter = b + b + a = 5.9 + 5.9 + 3.4 = 15.2 inches

Height of triangle = $\sqrt{(5.9)^{2} - (1.7)^{2} }$ = 5.65inches

Area of triangle = 1/2 base x height = 1/2 x 3.4 x 5.65 = 9.61 $inches^{2}$

For figure 9, perimeter = b + a + c = 8.2 + 4.1 + 9.17 = 21.47yards

Area of triangle = 1/2 x base x height = 1/2 x 8.2 x 4.1 = 16.81 $yards^{2}$

In conclusion, the perimeter and area of the given shapes are:

Figure 7; perimeter = 16.2mm, area = 12.64 square mm

Figure 8; perimeter = 15.2inches, area = 9.61 square inches

Figure 9; perimeter = 21.47yards, area = 16.81 square yards

Learn more about perimeter of plane shapes: brainly.com/question/2569205

#SPJ1

5 0

2 years ago