<h3>
Answer: x > 2</h3>
Work Shown:
5x - 14x < - 18
-9x < - 18
x > -18/(-9)
x > 2
The inequality sign flips when dividing both sides by a negative number.
Here's another approach you could take.
5x - 14x < - 18
-9x < -18
0 < -18+9x
18 < 9x
9x > 18
x > 18/9
x > 2
It's a slightly longer pathway, but it avoids a sign flip when you divide both sides by the positive number 9.
The sign flip happens two steps earlier when going from 18 < 9x to 9x > 18. In other words, A < B is the same as B > A.
Answer: 360 feet, or 3/44 of a mile
Step-by-step explanation: One yard is 3 feet, and 1760 yards are in a mile
Answer:
24g
Step-by-step explanation:
8g / 0.33 = 24.242424g
we have the function
Part a
For t=7
substitute in the given function
For t=14
For t=21
For t=28
For t=35
Observation: The values of E varies from -1 to 1, including the zero
Part B
Remember that
The Period goes from one peak to the next
so
Period=2pi/B
B=pi/14
Period=(2pi)/(pi/14)=2pi*14/pi=28
<h2>the period is 28 days</h2>
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
