Let the three consecutive odd numbers be x,x+2,x+4.
Given, their sum =219
Therefore, x+x+2+x+4=219
⇒3x+6=219
Subtract 6 from both the sides,
⇒3x+6−6=219−6
⇒3x=213
⇒x=71
The other numbers are x+2=71+2=73 and x+4=71+4=75.
Therefore, threee odd numbers are 71,73 and 75.
It is the numbers 3 through 7
Answer:
√(cd)*∛d
Step-by-step explanation:
This problem becomes a bit easier if we group the variables c and d together.
(cd)^(1/2)*d*(1/3) = c^(1/2)*d^(1/2+1/3)
Continuing, we get c^(1/2)*d^(5/6) (by adding the exponents 1/2 and 1/3)
Now c^(1/2) is equivalent to the radical form √c, and
d^(5/6) is equivalent to d^(5/3)^(1/2), which, as a radical, is √d(5/3).
Summarizing this:
(cd)^(1/2)*d*(1/3) = c^(1/2)*d^(1/2+1/3) = (cd)^(1/2)*d^(1/3),
which, in radical form, is √(cd)*∛d
Answer: (9)/(15)
Step-by-step explanation: