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3 years ago

write an equation in point-slope form that passes thru the given point and has the given slope? (5,2) m=3

Mathematics

2 answers:

Oduvanchick [21]3 years ago

8 0

Y - y1 = m(x - x1)
slope(m) = 3
(5,2)....x1 = 5 and y1 = 2
now we sub
y - 2 = 3(x - 5) <=== ur answer

Semmy [17]3 years ago

3 0

Ok so we are given the slope right? That means the line has a rise and run of 3 through the point 5,2 right? So we get y - 2 = 3(x - 5) Right? We are asked to answer it in point slope form right? So that’s the answer br />

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2(x + 4) − 1 = 2x + 7

Margarita [4]

Answer:

All real numbers are solutions to this problem.

Step-by-step explanation:

I) Simplify:

2(x + 4) - 1 = 2x + 7

x + 4 - 0.5 = x + 3.5 (Divide by 2)

x + 3.5 = x + 3.5 (Simplify <em>x + 4 - 0.5</em>)

x = x

II) Conclusion:

Any real number will work as a solution.

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2 years ago

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2 years ago

Please simplify this expression.<br> 1 + 4.25n + 32p – 3 + (–2p) + 54n

nata0808 [166]

Answer:

58.25n+30p-2

Step-by-step explanation:

Given the expression as;

1 + 4.25n + 32p – 3 + (–2p) + 54n

collect like terms

1-3+4.25n+54n+32p-2p

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58.25n+30p-2

I have copied one brainly user's answer, sorry for that...

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2 years ago

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4. Name the first five terms of the arithmetic sequence. a1 = -35, d=4

eduard

Answer:

Step-by-step explanation:

We first have to write the equation for the sequence, then finding the first five terms will be easy. Follow the formatting:

$a_n=a_1+d(n-1)$ and we are given enough info to fill in:

$a_n=-35+4(n-1)$ and

$a_n=-35+4n-4$ and

$a_n=-39+4n$ or in linear format:

$a_n=4n-39$ where n is the position of the number in the sequence. We already know the first term is -35.

The second term:

$a_2=4(2)-39$ so

$a_2=8-39$ and

$a_2=-31$

The third term:

$a_3=4(3)-39$ and

$a_3=12-39$ so

$a_3=-27$ and we could go on like this forever, but the nice thing about this is when we know the difference all we have to do is add it to each number to get to the next number.