There is no number in the hundreds place
I assume you meant to type x for %.
If not, basically back-substitute at the end of the solution.
F(x) = 4x - 3
Let y = F(x)
y = 4x - 3
x = 4y - 3
x - 3 = 4y
(x - 3)/4 = y
Let y = F^(-1)x
F^(-1)x = (x - 3)/4
If you want % in your answer, just replace x for % in your answer.
Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
68
I hope you understand this
Can you put it in any form instead of a point so I can correctly plot it in
