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shusha [124]
2 years ago
6

Tail-feather length in birds is sometimes a sexually dimorphic trait. That is, the trait differs substantially for males and for

females. Researchers studied the relationship between weight (x) and tail-feather length (y) in a sample of five wild male longtailed finches. Here are the data:
Weight Tail Length
20.5 82.5
19.1 82.5
15.9 67
16.7 70.5
15.7 73.5

The value of the linear correlation coefficient between weight and tail feather length is approximately : _________
Mathematics
1 answer:
GenaCL600 [577]2 years ago
4 0

Answer:

Step-by-step explanation:

it's about 18,  as per the graph

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Give right triangle PQR, which representa the value of sin (P)?
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5 0
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Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,
Sholpan [36]
A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
d^2=3^2+2^2
d^2=9+4
d^2=13
d= \sqrt{13}
We can conclude that the distance between my house and the movie theater is \sqrt{13}

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
d^2=6^2+5^2
d^2=36+25
d^2=61
d= \sqrt{61}
We can conclude that the distance between the police station and the airport is \sqrt{61}

C. Distance form the park to the Fire Station:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance from the park to the Fire Station is \sqrt{10}

Distance from the stadium to the mall:
d^2=2^2+1^2
d^2=4+1
d^2=5
d= \sqrt{5}
We can conclude that the distance from the stadium to the mall is \sqrt{5}

D. What is the distance between your house and the mall?
Answer:
d^2=4^2+4^2
d^2=16+16
d^2=32
d= \sqrt{32}
d=4 \sqrt{2}
We can conclude that the distance between my house and the mall is 4 \sqrt{2}

What is the distance between the movie theater and the school?
answer:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance between the movie theater and the school is \sqrt{10}

7 0
2 years ago
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