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SVEN [57.7K]
2 years ago
15

Can you help me solve this? -x/4<7

Mathematics
2 answers:
Anarel [89]2 years ago
8 0
I think the answer is x>-28
Makovka662 [10]2 years ago
3 0
Hello there,

The answer to your question would be:

x > -28

Hope I helped you...Good luck.
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John J. Parker worked 44 hours this week. He gets time-and-a-half for any hours beyond 40. How many regular pay hours did John w
Leni [432]
The answer you are looking for is 40 hours. they gave you the answer in the statement above when they said he gets time-and-a-half for any hours beyond 40. So he only worked 40 regular pay hours and got 4 hours overtime for time-and-a-half.
5 0
3 years ago
Determine if the expression – 6y5 z5 – is a polynomial or not. If it is a
sasho [114]

Answer:

it is not

Step-by-step explanation:

that is where I truly believe

8 0
2 years ago
Use the inverse of the function y = x2 − 18x to find the unknown values.
Lerok [7]

ANSWER

b=1, c=81, and d=9.

EXPLANATION

The given function is:

y={x}^{2}-18x

This function is the same as:

y={(x - 9)}^{2}-81

To find the inverse of this function, we interchange x and y.

x={(y-9)}^{2}-81

Solve for y:

x+81={(y- 9)}^{2}

Take square root of both sides:

\pm \sqrt{x + 81}=y-9

y=\pm \sqrt{x + 81}+9

Hence,

b=1, c=81, and d=9.

7 0
3 years ago
Read 2 more answers
3x+7=25 can some one help me with this problem it will be great
siniylev [52]

Answer =6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How do you check is the equation is a extraneous solution pr not?
vampirchik [111]

We can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.

<h3>What is the extraneous solution?</h3>

In mathematics, an extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem, such as the answer to an equation.

As we know from the definition the extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem.

Let's suppose the equation is:

\rm \sqrt{x+4} = x -2

Squaring both the sides:

x + 4 = (x - 2)²

x + 4 = x² - 4x + 4

x² -5x = 0

x = 0 or x = 5

Checking for the solution by plugging in the equation;

\rm \sqrt{5+4} = 5 -2

3 = 3

\rm \sqrt{0+4} = 0 -2

2 ≠ -2

The solution x = 0 shows extraneous solution.

Thus, we can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.

Learn more about the extraneous solution here:

brainly.com/question/14054707

#SPJ1

6 0
2 years ago
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