Answer:
the exact answer is 1.98
if we rationalize denominator we get root 0f 10 times pi divided by 5
root of 10 is about 3.1 (
) so we have 
≈ 9.6/5 = 1.92
Step-by-step explanation:
= 
Answer:
x = -15
Step-by-step explanation:
3x-5=2(2x+5)
Expand by using distributive property
3x - 5 = 4x + 10
Subtract 4x from both sides
3x - 5 - 4x = 4x + 10 - 4x
Simplifying
-x - 5 = 10
Add 5 to both sides
-x - 5 + 5 = 10 + 5
Simplifying
-x = 15
Divide both sides by -1
x = -15
The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
_____
There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
Answer:
x=13
Step-by-step explanation:
you have to isolate the variable
3(x-4)=x+14
distribute
3x-12=x+14
subtract 14 from each side
3x-26=x
subtract 3x from each side
-26=-2x
divide each side by -2
13=x
flip sides
x=13
hope this helps!!! :)
Answer:
0.75 mg
Step-by-step explanation:
From the question given above the following data were obtained:
Original amount (N₀) = 1.5 mg
Half-life (t₁/₂) = 6 years
Time (t) = 6 years
Amount remaining (N) =.?
Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:
Half-life (t₁/₂) = 6 years
Time (t) = 6 years
Number of half-lives (n) =?
n = t / t₁/₂
n = 6/6
n = 1
Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:
Original amount (N₀) = 1.5 mg
Half-life (t₁/₂) = 6 years
Number of half-lives (n) = 1
Amount remaining (N) =.?
N = 1/2ⁿ × N₀
N = 1/2¹ × 1.5
N = 1/2 × 1.5
N = 0.5 × 1.5
N = 0.75 mg
Thus, 0.75 mg of the sample is remaining.
