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3 years ago

There are 37 ants, 39 worms, 12 moths, and 11 beetles living in a big garden. Find the sum. Explain your work.

Mathematics

1 answer:

Bas_tet [7]3 years ago

8 0

Answer: 99 insects altogether.

Step-by-step explanation:

Adding two numbers add a time is easiest, rather than adding all four numbers together.

First, add 37 + 39 =. 76

add 12 to that sum, which equals 88.

76+12=88

to that sum, add the final number, 11.

88+11=99

so there are 99 bugs altogether.

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Solve each equation. If necessary, round to the nearest ten-thousandth. 8x=444

wel

The solution of the given equation by rounding off it to the nearest ten-thousandth is 55.5000.

What is a round-off of the digit?

In mathematics, a round-off is defined as an approximation of the given number to a fewer number of significant digits by taking into consideration some rules.

For eg: 13.58 ~ 13.6

Solving the given equation: 8 x = 444

We are given that 8 x = 444 —- 1

x = 444 / 8

= 55.5

Hence, the solution of the given equation rounded off to the nearest ten-thousandth is 55.5000.

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7 months ago

Market-share-analysis company Net Applications monitors and reports on Internet browser usage. According to Net Applications, in

EastWind [94]

The answer is c. I believe so

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3 years ago

Using principle of mathematical induction prove that 6^-1 divisble by 5 .

salantis [7]

I suppose the claim is $5 \mid 6^n - 1$ for $n\in\Bbb N$ .

When $n=1$ , we have $6^1 - 1 = 6 - 1 = 5$ , and of course 5 divides 5.

Assume the claim holds for $n=k$ , that $5 \mid 6^k - 1$ . We want to use this to show it holds for $n=k+1$ , that $5 \mid 6^{k+1} - 1$ .

We have

$6^{k+1} - 1 = \left(6^{k+1} - 6\right) + \left(6 - 1) = 6\left(6^k - 1\right) + 5$

Since $5 \mid 6^k - 1$ , we can write $6^k - 1 = 5\ell$ for some integer $\ell$ . Then

$6^{k+1} - 1 = 6\cdot5\ell + 5 = 5(6\ell + 1)$

which is clearly divisible by 5. QED

5 0

1 year ago

What is 6 - 5/6 equele

elena-s [515]

Answer:

31/6

Step-by-step explanation:

Write all numbers above the common denominator so 6-5/6

Multiply 6 by 6

Then we have 36 -5 / 6

Subtract the numbers so 36 -5 = 31 and 6 stays the same

We end up with 31/6 or 5 1/6 or 5.16 as Alternative form

8 0

3 years ago

Consider parallelogram △MNOP shown above.

Nina [5.8K]

To find the length of the sides of this parallelogram, we just have to calculate the length of each side and then proceed to find the perimeter.

The perimeter of the parallelogram is 13 units.

<h3>Perimeter of a Parallelogram</h3>

To calculate the perimeter of a parallelogram, we need the values of the length of the sides. However, if we have the details of two opposite sides, we can find the perimeter of the parallelogram because opposite sides are equal.

Length of MN = 2units

Length of MP = 4.5 units

The perimeter of MNOP can be calculated as

$perimeter = 2(MP + MN)$

We can substitute the values into the equation and solve

$perimeter = 2(MP + MN)\\perimeter = 2 * (4.5 + 2)\\perimeter = 2 * 6.5\\perimeter = 13$

The perimeter of the parallelogram is 13 units.

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6 0

1 year ago