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3 years ago

7

1/4 of the seventh grade students went on a field trip to the Alamo. If there a 388 students in the seventh grade, how many stud

ents went on the field trip?

1 answer:

Afina-wow [57]3 years ago

5 0

Answer: 97 students

Step-by-step explanation:

Simple! We need to split 388 into four equal parts, so

388 / 4 = 97

Hope this helps!

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490 tickets is 1,230

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3 years ago

The sum of three numbers is 26. Twice the first minus the second is the third less 2. The third is the second minus 3 times the

Agata [3.3K]

Let a, b, c represent the three numbers. The problem statement gives rise to three equations:

a +b +c = 26
2a -b = c -2
-3a +b = c

Adding the first two equations gives

... (a +b +c) +(2a -b) = (26) +(c -2)

... 3a +c = 24 +c . . . . . simplify

... 3a = 24 . . . . . . . . . . subtract c

... a = 8 . . . . . . . . . . . . divide by 3

Adding the second and third equations gives ...

... (2a -b) +(-3a +b) = (c -2) +(c)

... -a = 2c -2 . . . . simplify

... -6 = 2c . . . . . . add 2, substitute for a

... -3 = c . . . . . . . . divide by 2

Using the third equation we can find b.

... -3·8 +b = -3 . . . . substitute for a and c

... b = 21 . . . . . . . . .add 24

The numbers are 8, 21, -3.

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The method above is sort of "ad hoc", taking advantage of the numbers in this particular set of equations. You can use more formal methods of Gaussian elimination or Cramer's Rule to solve these by just following a procedure. Or, your graphing calculator can do it for you.

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Nimfa-mama [501]

This is something you would do through trial and error. At least, that's the approach I took. I'm not sure if there is any algorithm to solve. The solution I got is shown in the attached image below. There are probably other solutions possible. The trick is to keep each number separate but not too far away so that the other numbers to be filled in later don't get too crowded to their neighbor.

Side note: any mirror copy of what I posted would work as well since you can flip the page around and it's effectively the same solution.

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4 years ago

Select all the correct graphs.<br> Choose the graphs that indicate equations with no solution.

Natali [406]

Answer:

The first and last graph.

General Formulas and Concepts:

<u>Algebra I</u>

Solving systems of equations graphically

Step-by-step explanation:

In order for a systems of equations to have a solution set, the 2 graphs must intersect at at least 1 point. Here, we see that graphs 1 and 5 do not intersect each other at all.

Therefore, the rest of the graphs have solutions and #1 and #5 do no have any solutions.

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3 years ago