3 years ago

In ∆abc, what is the value of cos b?

Mathematics

1 answer:

Rzqust [24]3 years ago

4 0

$c^2=a^2+b^2-2ab\cos\beta\\\\2ab\cos\beta=a^2+b^2-c^2\\\\\boxed{\cos\beta=\dfrac{a^2+b^2-c^2}{2ab}}$

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