In diagram below, ab and bc are tangent to o. what is the measure of abc.

Mathematics

2 answers:

IgorLugansk [536]3 years ago

7 0

Answer:

Option A. will be the answer.

Step-by-step explanation:

It is given in the diagram attached, AB and BC are the tangents to circle O.

We have to find the measure of ∠ABC.

By the theorem,

Measure of ∠ABC which inscribed within the tangents will be $=\frac{1}{2}(arcADC-arcAC)$

$=\frac{1}{2}(226-134)$

$=\frac{1}{2}(92)$

= 46°

Option A. will be the answer.

hichkok12 [17]3 years ago

5 0

Check the picture below.

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If a cone with a diameter of 10 m has a surface area of 190.6m2, find its slant height. Round to the nearest tenth.

alukav5142 [94]

Answer: The slant height of the cone is 65.6 m

Step-by-step explanation:

Given: The diameter of a cone = 10 m

Surface area of cone = 190.6 m²

To find: Slant height

Diameter of cone = 10 m

Therefore Radius of cone = $\dfrac{\text {Diameter }}{2} = \dfrac{10}{2} =5m$

As we know that surface area of a cone is given by

$S.A. = \pi r(l+r)$

Where S.A. is surface area , r is the radius of cone and l is the slant height of the cone.

Let Slant height = l

So we have

$190.6 = \dfrac{22}{7} \times 5 ( 5+l)\\\\\Rightarrow 5+l= \dfrac{190.6 \times 7}{22}\\\\\Rightarrow l= \dfrac{1334.2}{22}+5\approx 60.64+5 = 65.64\approx65.6$