Answer:
(-∞,4)
Step-by-step explanation:
the value is going down from the right until it reaches the vertex
The answer is: "
41 / 11 " ; or, write as: "
41 : 11 " .
__________________________________________________________Explanation:__________________________________________________________72/99 = (72÷9) / (99÷9) = 8/ 11 .
So, 3.727272727272... = "3

" .
→ "3

" = [(11 *3) + 8] / 11 = (33 + 8) / 11 = 41 / 11 .
__________________________________________________________ "41 / 11" cannot be simplified any further; so the answer is:
__________________________________________________________ "
41 / 11 " ; or, write as: "
41 : 11 " .
__________________________________________________________
Answer: 0.5
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Answer:

Step-by-step explanation:
We are given that


y(0)=0
y'(0)=1
By comparing with

We get


q(x)=0
p(x),q(x) and g(x) are continuous for all real values of x except 3.
Interval on which p(x),q(x) and g(x) are continuous
and (3,
By unique existence theorem
Largest interval which contains 0=
Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=
6x3=18 so choice number 1 is true