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Maksim231197 [3]
2 years ago
11

Write the equation of a parabola with a vertex at (0,0), a focus at (2,0), and directrix x=-2

Mathematics
1 answer:
kkurt [141]2 years ago
8 0
The directrix is x=-2, which means the parabola opens horizontally instead of vertically. The equation is (y - k)²<span> = 4p (x - h), where the </span>focus<span> is (h + p, k) and the </span>directrix<span> is x = h - p
in this case, h+p=2, k=0, and h-p=-2
solve for h and p: h=0, p=2
plug the numbers into the equation: (y-0)</span>²=4*2(x-0)
simplify: y²=8x
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3x−12≥15<br><br> 2x−5≤9<br><br> 5x+8≤53<br><br> 3x−5≥16
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Answer:

Step-by-step explanation:

A) 3x−12≥15

3x ≥ 15 + 12

3x ≥ 27

or x≥ 9

B) 2x−5≤9

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2x ≤ 14

or x ≤ 7

C) 5x+8≤53

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or x ≤ 9

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Have a good day!

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3 years ago
Based only on the given information, it is guaranteed that AC = BC.
Alenkasestr [34]
False :) hope it help
5 0
3 years ago
Read 2 more answers
Write an expression that is equivalent to 3/5 (3y+15)<br> 3/5y +9, 3/5y+15, 9/5y+9, 9/5y + 15?
NISA [10]
Given the expression

\frac{3}{5} (3y+15)

The expression that is equivalent to the given expression is given by:

\frac{3}{5} (3y+15)= \frac{9}{5} y+ \frac{3}{5} (15)= \frac{9}{5} y+9
6 0
3 years ago
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