Question

Use the table of integrals, or a computer or calculator with symbolic integration capabilities, to find the indefinite integral.

Answer 1

Answer:

$\frac{1}{6} (-\frac{3}{(2x+3)} -\ln x+\ln(2x+3))+C$

Step-by-step explanation:

We are given:  $\int\frac{-6}{x(4x+6)^2} dx$

$x = \frac{3}{2}\tan t\\dx = \frac{3}{2}(\tan ^2 t +1) dt$

$\int\frac{-6}{x(4x+6)^2} dx= \frac{1}{6} \int(-\frac{6}{(3+2x)^2} -\frac{1}{x} +\frac{2}{3+2x})dx=\\\\= \frac{1}{6} (-\frac{3}{(2x+3)} -\ln x+\ln(2x+3))+C$