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Natasha_Volkova [10]
3 years ago
10

Find an expression for the function f(x) whose graph is a line passing through the points (8,-5) and (-9,2). f(x)=

Mathematics
2 answers:
kolbaska11 [484]3 years ago
8 0

Answer: f(x) = - 7x/17 - 29/17

Step-by-step explanation:

The expression for the function f(x) would be represented in the slope-intercept form, y = mx + c

Where

c represents the y intercept.

m represents the slope of the line.

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent

change in the value of y = y2 - y1

Change in value of x = x2 -x1

The line passes through (8, - 5) and (- 9, 2),

y2 = 2

y1 = - 5

x2 = - 9

x1 = 8

Slope,m = ( 2 - - 5)/(- 9 - 8) = 7/- 17 =

- 7/17

To determine the intercept, we would substitute x = 8, y = - 5 and m = - 7/17 into

y = mx + c. It becomes

- 5 = - 7/17 × 8 + c

- 5 = - 56/17 + c

c = - 5 + 56/17

c = - 29/17

The equation becomes

f(x) = - 7x/17 - 29/17

saw5 [17]3 years ago
8 0

Answer:

f(x)=-7/17x-29/17

Step-by-step explanation:

f(x) =y

(8,-5)..........x1 =8,y1=-5

(-9,2)..........x2=-9,y2 =2

m=(y2-y1) /(x2-x1)

m=(2-(-5))/(-9-8)

m=(2+5)/(-17)

m=7/(-17)

m=-7/17

y-y1=m(x-x1)

y-(-5)=-7/17(x - 8)

y+5=-7/17x+56/17

y=-7/17x+56/17-5

y=-7/17x+56/17-85/17

y=-7/17x-29/17

f(x)=-7/17x-29/17

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Answer:

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age  \leq 3}\end{array}\right

i.e after the first year ;

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Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 0 \  \leq  age   \leq  2 }\\{0 \  \leq  age   \leq 3}\end{array}\right]

Also , the age transition matrix is as follows:

L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]

After 1 year ; the age distribution vector will be :

x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]  \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq 1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age   \leq  3}\end{array}\right

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89 hours

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First solve all the deductions.

For each multiply the $10, which you are paid, and the percentage.

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For Fed tax: $10 x 0.12 = $1.2 per hr

For State tax: $10  x 0.08 = $0.8 per hr

Now subtract the remaining pay:

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