Let x be the length of the train.
On the basis of the observer;
Speed of the train = x/6
On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20
Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.
Therefore,
Length of train = 150 m
Speed of train = 25 m/s
Answer:
4x +6
Step-by-step explanation:
No explanation
Straight answer
Answer:
Step-by-step explanation:
I'm not sure if I am too late to answer this but the trick to this is to reflect the function over the line y = x.
Basically, if you have the point (-2, 3)
you turn in into (2, -3) and you'll be good. (switch the two coordinates and take the negative for both.)
Ik its messy but i hope this helps:]
The sides of the angle are the lengths which it is formed
