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frez [133]
3 years ago
7

Can someone please answer. There's one question. There's a picture. Thank you!

Mathematics
1 answer:
QveST [7]3 years ago
5 0
The volume of a cylinder is r^2\pidh
enter values, then you get 3.53, multiply that by the BTU, the answer is 8888 BTU
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HELPPPP. Need help asap.
mamaluj [8]

Answer:

Just learned this-

They are both 1 because of it being to the power of zero and if you type the both in like...

Step-by-step explanation:

sin(73)^0 you get 1

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6 0
3 years ago
Find the quotient. (6 1/2 ÷ 3 2/3) ....1 17/22 23 5/6 21/3 2 3/4
Karo-lina-s [1.5K]

Answer:

1 17/22

Step-by-step explanation:

7 0
2 years ago
Kyle has a total of 16 coins in his pocket. All the coins are nickels or quarters, and they have a total value of $2.20. How man
kari74 [83]
44 nickels because you just add 5 intill you get 220
7 0
3 years ago
Read 2 more answers
Need Help ASAP WILL MARK YOU BRAINLYEST
Dima020 [189]

he divided by 2 instead of taking the square root so the actual answer should be 26 and for the second the 20 is across from the  90 so its suppose to be c

the answer should be 16

5 0
3 years ago
The service department of a luxury car dealership conducted research on the amount of time its service technicians spend on each
mart [117]

Answer:

Probability that the mean service time is between 1 and 2 hours is 0.96764.

Step-by-step explanation:

We are given that a systematic random sample of 100 service appointments has been collected.

The 100 appointments showed an average preparation time of 90 minutes with a standard deviation of 140 minutes.

<u><em>Let </em></u>\bar X<u><em> = sample mean service time</em></u>

The z-score probability distribution for sample mean is given by;

                             Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = average preparation time = 90 minutes

           \sigma = standard deviation = 140 minutes

           n = sample of appointments = 100

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, probability that the mean service time is between 60 and 120 minutes is given by = P(60 minutes < \bar X < 120 minutes)

P(60 minutes < \bar X < 120 minutes) = P(\bar X < 120 min) - P(\bar X \leq 60 min)  

  P(\bar X < 120 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{120-90}{\frac{140}{\sqrt{100} } } ) = P(Z < 2.14) = 0.98382

  P(\bar X \leq 60 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{60-90}{\frac{140}{\sqrt{100} } } ) = P(Z \leq -2.14) = 1 - P(Z < 2.14)

                                                        = 1 - 0.98382 = 0.01618

<em>The above probability is calculated by looking at the value of x = 2.14 in the z table which has an area of 0.98382.</em>

Therefore, P(60 min < \bar X < 120 min) = 0.98382 - 0.01618 = <u>0.96764</u>

7 0
3 years ago
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