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miskamm [114]
3 years ago
11

There are 17 students in a class. On the day the test was given, John was absent. The other 16 students took the test, and their

average score is 77. The next day John took the test, and with his grade included, the new average is 78. What is John's grade on the test?
Mathematics
2 answers:
Tju [1.3M]3 years ago
5 0

Answer:

Step-by-step explanation:

Total scores of 16 students with an average score of 77= 16x77= 1232 scores.

The nextday scores of 17 students with an average scores of 78 John inclusive =77x78 = 1326.

Therefore, the grade of John in the test, = 1326 - 1232

= 94grades.

e-lub [12.9K]3 years ago
4 0

Answer:

John got 94 marks

Step-by-step explanation:

average = total numbers/ no. of students

77= x/16--------------1

78=x+y/17------------2

From 1 :      x= 77*16= 1232--------------3

From 2:       x+y= 78*17=  1326---------4

subtracting 3 from 4

y= 1326-1232= 94

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Answer:

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Step-by-step explanation:

From the information given the table appears as;

x            f(x)=2^x              g(x)=0.5^x

2               4                            0.25

1                 2                           0.5

0                1                             1

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Plotting the two graphs to view the trends;

In the graph of f(x)=2^x against x you notice a curve with increasing positive slope.

In the graph of g(x)=0.5^x against x you notice a curve with a negative slope that is increasing.

In combining both graphs you notice that f(x) and g(x) are reflections over the y-axis.

Correct answer is ;The functions f(x) and g(x) are reflections over the y-axis.

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3 years ago
What is the slope of the line? question 3
valentina_108 [34]

Answer:

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Step-by-step explanation:

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weqwewe [10]
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Christian randomly selects students from his grade to rate a math test as easy, moderate, or difficult. Of the students he surve
IRINA_888 [86]

Answer:

84

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2 years ago
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Komok [63]
The inequality is 

7- \frac{2}{b}\ \textless \ \frac{5}{b}

write 7 as 7b/b to have all the expressions in common denominator:

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\frac{7b-2}{b} \ \textless \ \frac{5}{b}

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this means that for values of b to the left of 0 and to the right of 1, the expression is positive, and for values of b in (0, 1), the expression is negative.

that is \frac{7(b-1)}{b}\ \textless \ 0 for b∈(0, 1)

Answer: (0, 1)
8 0
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