Answer:
b = -2c ± [√(4π²c² + πA)]/π
Step-by-step explanation:
A = 4πbc + πb^2
A = 4πbc + πb²
πb² + 4πbc - A = 0
Using the quadratic formula to solve this quadratic equation.
The quadratic formula for the quadratic equation, pb² + qb + r = 0, is given as
b = [-q ± √(q² - 4pr)] ÷ 2p
Comparing
πb² + 4πbc - A = 0 with pb² + qb + r = 0,
p = π
q = 4πc
r = -A
b = [-q ± √(q² - 4pr)] ÷ 2p
b = {-4πc ± √[(4πc)² - 4(π)(-A)]} ÷ 2π
b = {-4πc ± √[16π²c² + 4πA]} ÷ 2π
b = (-4πc/2π) ± {√[16π²c² + 4πA] ÷ 2π}
b = -2c ± [√(4π²c² + πA)]/π
Hope this Helps!!!
Since in Jimmy's 90 times die roll six appeared 11 times, so the probability of face of sixes appearing is:
.
Thus , when the die is rolled 1500 times then it is obvious that the number of times the face of six will appear will also increase proportionately.
This proportionate increase in the number of times the face of six will appear will be given thus:
If six appears 11 times in 90 rolls then to find how many times it will appear in 1500 rolls is calculated as
where x is the number of times the face of six will appear.
Thus, expression gives:

Therefore, Jimmy can six's approximately 183 times if he rolled the die 1500 times.
Answer:
its close 9.45
Step-by-step explanation:
7(x+9)=132
7x+63=132
7x=132-63
7x=69
x=69/7
x=9.45
Answer: si = 1500 ci =1250
Step-by-step explanation:
Answer:
The answer is option D, 50. :)