Answer:
the answer would be 777.61791764707.
Multiply first the mass given in kilograms by 1000 in order to convert it to grams.
(0.23 kg) (1000 g / 1kg) = 230 g
Then, divide the mass in gram by the molar mass of SO2
molar mass of SO2 = 64.044 g/mol
Solving for the number of moles,
(230 g)(1 mol/64.044g) = 3.59 moles
Thus, there are approximately 3.59 moles of SO2 present in 0.23 kg of SO2.
Explanation:
<h2>Radium(Ra)=> </h2>
atomic number=88
<h2>BERYLLIUM (Be)=></h2>
atomic number =4
why is Ra larger than Be
<h3>1. since the atomic number of Ra is greater than Be, the number of electrons is more, which means there are more number of shells present in Ra than Be. </h3><h2>(atomic Radius)</h2>
<h2>2. the more the valence electron (excluding fully filled ones) the less is the nuclear attraction force</h2><h3>since Ra has more valence electron in its outermost shell, the nuclear attraction force is less which means that Ra 's size is greater than Be.</h3>
hope it helps:)
Answer: 0.52849 j /g °C
Explanation:
Given the following :
Mass of metal = 36g
Δ Temperature of metal = (28.4 - 99)°C = - 70.6°C
Mass of water = 70g
Δ in temperature of water = (28.4 - 24.0) = 4.4°C
Heat lost by metal = (heat gained by water + heat gained by calorimeter)
Quantity of heat(q) = mcΔT
Where; m = mass of object ; c = specific heat capacity of object
Heat lost by metal:
- (36 × c × - 70.6) = 2541.6c - - - - (1)
Heta gained by water and calorimeter :
(70 × 4.184 × 4.4) + (12.4 × 4.4) = 1288.672 + 54.56 = 1343.232 - - - - (2)
Equating (1) and (2)
2541.6c = 1343.232
c = 1343.232 / 2541.6
c = 0.52849 j /g °C
Answer:
im pretty sure its b
Explanation:
im sorry if im wrong i tried my best