Answer is:<span>the yield is 50%.
</span>
Chemical reaction: C + O₂ → CO₂.
n(C) = 0.3 mol; amount of substance.
n(O₂) = 0.3 mol.
From chemical reaction: n(C) : n(CO₂) = 1 : 1.
n(CO₂) = 0.3 mol.
M(CO₂) = 44 g/mol; molar mass of caron(IV) oxide.
m(CO₂) = n(CO₂) · M(CO₂).
m(CO₂) =0.3 mol · 44 g/mol.
m(CO₂) = 13.2 g; mass of carbon(IV) oxide.
the yield = 6.6 g ÷ 13.2 g · 100%.
the yield = 50%.
Answer:
The final volume when pressure is changed is 126.1mL
Explanation:
Based on Boyle's law, in a gas the volume is inversely proportional to its pressure when temperature remains constant. The equation is:
P₁V₁ = P₂V₂
<em>Where P is pressure and V volume of 1, intial state and 2, final state.</em>
<em />
Computing the values of the problem:
350mmHg*200mL = 555mmHgV₂
126.1mmHg = V₂
<h3>The final volume when pressure is changed is 126.1mL</h3>
Answer:
The pOH is 4, 44 and the solution is basic.
Explanation:
The pOH is a measure of the concentration of OH (hydroxyl) ions in the solution.
The pOH is calculated as :
pOH = -log (OH-)= -log (3.67 x 10-5 )= 4, 44. In this case, the solution is basic.
The p0H scale ranges from values of 0 to 14 (less than 7.0 is basic and greater than 7.0 is acidic, a pH = 7.0 is neutral)
Answer:
it’s mass was greater than when it started
Explanation:
When a metal is coated with another metal, the plating metal deposits on the plated metal. Usually, the plating metal functions as the anode while the plated metal functions on the cathode. The anode metal is oxidized and reduced at the cathode and become deposited on the cathode material. This increases the mass of the cathode. Hence the mass of the silver/gold product is greater than the mass of silver at the beginning of the electroplating process.
