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horrorfan [7]
2 years ago
12

Although the final reaction of the hexose portion of glycolysis yields DHAP and G-3-P, further reactions proceed as if there had

been 2 G-3-P made per glucose. Why?
a. G-3-phosphate is used for Stage II of glycolysis so the system is more likely to produce more of it than Dihydroxyactone phosphate.

b. Because the ΔGo of the conversion between the two is negative.

c. Because the ΔGo of the conversion between the two is positive

d. Because nonequililbrium conditions favor the conversion of DHAP to G-3-P

e. None of the above
Biology
1 answer:
ziro4ka [17]2 years ago
3 0

Answer:

a. G-3-phosphate is used for Stage II of glycolysis so the system is more likely to produce more of it than Dihydroxyactone phosphate.

Explanation:

G-3-P and DHAP are isomers of each other therefore they can convert it self to other form by an enzyme called triose-phosphate  isomerase. As G-3-P is a reaction substrate for further steps of glycolysis therefore all the DHAP is depleted which results in the formation of two G-3-P molecules from each glucose.

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