Answer:
// here is code in the C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main() {
// variable to store the input
int birth_month,birth_year;
cout<<"enter birth month:";
// read the birth month
cin>>birth_month;
cout<<"enter birth year:";
// read the birth year
cin>>birth_year;
// print the output
cout<<birth_month<<"/"<<birth_year<<endl;
return 0;
}
Explanation:
Declare two variables to store the birth month and birth year.Read the inputs from the user and assign it the variables.Print the birth month and year separated by a slash "/".
Output:
enter birth month:1
enter birth year:2000
1/2000
Answer:
I forgot give me time to think abt it cuh
Explanation:
Answer:
"Crowdsourcing" is the correct answer for the above question.
Explanation:
- Crowdsourcing is a term from which any organization advertises the thinks or can get the ideas or solutions for any particular problem.
- It is a term that refers to the problem to the number of solvers to achieve the result correct and frequent.
- For example, If anyone wants to prepare the two websites. Then he assigns the works to the number of people and the works done faster with the help of this.
- The above question states that some websites can be successful with the help of the type of work. They are successful with the help of crowdsourced work. Because it saves time. So the answer is Crowdsourcing.
Answer:
The codes below implement the problem statements
Explanation:
public class Percentages {
public static void computePercent (int a,int b)
{
System.out.println(a+" is "+(a*100/b)+"% of "+b);
}
public static void main(String []args)
{
int a=2;
int b=5;
computePercent(a,b);
computePercent(b,a);
}
}
<u>
</u>
<u>Part(b)
</u>
import java.util.*;
public class Percentages {
public static void computePercent (int a,int b)
{
System.out.println(a+" is "+(a*100/b)+"% of "+b);
}
public static void main(String []args)
{
Scanner s= new Scanner(System.in);
int a=s.nextInt();
int b=s.nextInt();
computePercent(a,b);
computePercent(b,a);
}
}
Answer: Strong 128-bit encryption.
Explanation: An individual character corresponds to 8 bits . So if there are 16 characters then,
16
8=128 bits keys
This makes the 128 bit key encryption the strongest amongst all other options.It is strongest because it is almost impossible to decode the 128-character key by any method e.g.-brute-force method.
Other options are incorrect because the characters given by the other bits are as follows: 
=32 characters
=64 characters
=128 characters
Thus, the strongest character key is of 128 bits. for cipher.
