Answer and Explanation:
Given that total number of records in a file = 100000
Each record consists of= 240 bytes
Given that B= 2400 bytes.
Then total blocks in file = 100000 records * 240 / 2400
= 10000 blocks.
Time that will take for exhaustive read
= s + r + b.btt
= 16 + 8.3 + (10000) * 0.8
= 8024.3 msec
Now as per given X be the number of records that are searched randomly and it takes more than exhaustive read time.
Hence, X (s + r + btt) > 8024.3
X (16+8.3+0.8) > 8024.3
X > 8024.3/25.1
So that, X > 319.69
Hence, atleast 320 random reads should be made to search the file
The correct answer is A I believe.
In a bus network, a single communication path connects the network server,departamental servers, workstations, and peripheral devices.
c. bus network
