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boyakko [2]
4 years ago
15

To keep cylindrical flower vases from spilling, a designer is planning to enlarge the original area of the base by 25%. The new

vase should have the same volume as the original. How should the designer change the height of the vase?
Mathematics
1 answer:
spin [16.1K]4 years ago
4 0

Answer:

To keep the same volume, the designer needs to decrease the height of the vase by 20%


Step-by-step explanation:

Volume of cylinder formula is  V=\pi r^2 h


Area of base is  \pi r^2, if this area is increased by 25%, the new area of base would be:

\pi r^2 + \frac{25}{100}(\pi r^2)\\=\pi r^2 + (0.25)(\pi r^2)\\=1.25\pi r^2


Since volume would be same, we can make the height as:

V=\pi r^2 h\\V=(1.25\pi r^2)(\frac{h}{1.25})\\V=\pi r^2h


Thus, we can see that the height needs to be divided by 1.25, which we can write in fractional form as:

\frac{h}{1.25}\\=\frac{h}{\frac{5}{4}}\\=h*\frac{4}{5}\\=h*(0.8)


Thus, height needs to be \frac{4}{5} of original (or 80% of original)


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