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2 years ago

Find all real numbers x such that 6x-21>5

1 answer:

4 0

$~~~~~~6x-21 > 5\\\\\implies 6x > 5+21\\\\\implies 6x > 26\\\\\implies x > \dfrac{26}6\\ \\\implies x > \dfrac{13}{3}\\$

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Move each inequality next to the number line it represents.<br> Number Line<br> Inequality

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1. x > -2
2. x ≤ -2
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4. x < -2

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3 years ago

Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc

In-s [12.5K]

Answer:

$\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

$L^2 = y^2 + x^2$

$\implies L = \sqrt{y^2 + x^2}$ ,

Differentiating with respect to time (t),

$\frac{dL}{dt}=\frac{d}{dt}(\sqrt{x^2 + y^2})$

$=\frac{1}{2\sqrt{x^2 + y^2}}\frac{d}{dt}(x^2 + y^2)$

$=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})$

$=\frac{1}{\sqrt{x^2 +y^2}}(x\frac{dx}{dt}+y\frac{dy}{dt})$

Here,

$\frac{dy}{dt}=-6\text{ ft per sec}$

Also, $\frac{dL}{dt} = 0$ ( Ladder length = constant ),

$\implies \frac{1}{\sqrt{x^2 +y^2}}(x(-6)+y\frac{dy}{dt})=0$

$-6x + y\frac{dy}{dt}=0$

$y\frac{dy}{dt}=6x$

$\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Which is the required notation.

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3 years ago

Help me i hate word problems

VMariaS [17]

Is that all? My Algebra is freackin hard compared to this. Anyways, The way I understand this, is that we will have 3 (liters of water) +0.5 (half a liter of lemonade) =3.5 liters of liquid

so the question would be: how many times does fit into 3.5?

if you want to divide by a fraction, you need to multiply by the reverse of it.

so the answer is: 10 servings of lemonade ( and a little bit will be left over for half a serving).
Hope this helps!

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3 years ago

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Thepotemich [5.8K]

Answer:

3/4 pizza is left. If you want an explanation, ask me ;>

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3 years ago

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Nesterboy [21]

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