2/3 of the product of 3/8 and 16

1 answer:

7 0

Hi there!

To solve this problem, we should first find the product of 3/8 and 16 and multiply the solution by 2/3.

Let's find the product first.

3/8 × 16 = 48/8

Simplify.

48/8 = 48 ÷ 8 = 6

Now, we find 2/3 of 6.

6 ÷ 3 × 2 = 2 × 2 = 4

So, your answer is 4.

Hope this helps!

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Help me plzzzzzzzzz!!!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer: ( 12 , 9 )

Step-by-step explanation:

The formula for finding the coordinate of points when a line is externally divided in a given ratio is given by :

x = $\frac{p x_{2}+q x_{1}}{p+q}$

y = $\frac{p y_{2}+q y_{1}}{p+q}$

From the question

$x_{1}$ = 2

$x_{2}$ = ?

x = 4

$y_{1}$ = -1

$y_{2}$ = ?

y = 1

p = 1

q = 4

substituting the values into the formula ,we have

x = $\frac{p x_{2}+q x_{1}}{p+q}$

4 = $\frac{1(x_{2})+4(2) }{1+4}$

4 = $\frac{x_{2}+8}{5}$

$x_{2}$ + 8 = 20

$x_{2}$ = 12

Also

y = $\frac{p y_{2}+q y_{1}}{p+q}$

1 = $\frac{y_{2}+4(-1)}{5}$

$y_{2}$ - 4 = 5

$y_{2}$ = 9

Therefore , the end of the stencil is located at point ( 12 , 9 )

5 0

3 years ago

Points B, D, and F are midpoints of the sides of ΔACE. EC = 38 and DF = 16. Find AC. The diagram is not to scale.

Lunna [17]

Answer: The measure of AC is 32.

Explanation:

It is given that the Points B, D, and F are midpoints of the sides of ΔACE. EC = 38 and DF = 16.

The midpoint theorem states that the if a line segments connecting two midpoints then the line is parallel to the third side and it's length is half of the third side.

Since F and D are midpoints of AE and EC respectively.

So by midpoint theorem length of AC is twice of DF.

$AC=2\times DF$