<u>Given:</u>
The equation of the line passes through the point (6,9) and is perpendicular to the line whose equation is 
We need to determine the equation of the line.
<u>Slope</u>:
Let us convert the equation to slope - intercept form.


From the above equation, the slope is 
Since, the lines are perpendicular, the slope of the line can be determined using the formula,



Therefore, the slope of the equation is 
<u>Equation of the line:</u>
The equation of the line can be determined using the formula,

Substituting the point (6,9) and the slope
in the above formula, we get;

Simplifying the terms, we get;



Thus, the equation of the line is 