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SSSSS [86.1K]
3 years ago
12

Simplify (square root of 2)(cube root of 2)

Mathematics
1 answer:
KIM [24]3 years ago
8 0

The square root of 2 is 1.41421356237. The cubes root of 2 is 1.25992104989. I hope his helped.

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For the following inequality, indicate whether the boundary line should be dashed or solid. x ≤ 5
lukranit [14]
Answer: The boundary lien should be solid because the inequality indicates that the value “5” is included. Remember: “greater than or equal to; less than or equal to,” as solid lines. While “<;>” are dashed lines.
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4 years ago
HELP PLEASE IM BEGGING PLEASE PLEASE PLEASE
nasty-shy [4]

Answer:

h - 18 = 67

Step-by-step explanation:

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4 0
3 years ago
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1) Determine the discriminant of the 2nd degree equation below:
Aleksandr-060686 [28]

\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}

We have, Discriminant formula for finding roots:

\large{ \boxed{ \rm{x =  \frac{  - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a} }}}

Here,

  • x is the root of the equation.
  • a is the coefficient of x^2
  • b is the coefficient of x
  • c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5\pm  \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5  \pm  \sqrt{25 - 24} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5 \pm 1}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 2 \: or  - 3}}}

❒ p(x) = x^2 + 2x + 1 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{  - 2 \pm  \sqrt{ {2}^{2}  - 4 \times 1 \times 1} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm 0}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 1 \: or \:  - 1}}}

❒ p(x) = x^2 - x - 20 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - ( - 1) \pm  \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{1 \pm 9}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \:  - 4}}}

❒ p(x) = x^2 - 3x - 4 = 0

\large{ \rm{ \longrightarrow \: x =   \dfrac{  - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{3 \pm \sqrt{9  + 16} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{3  \pm 5}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \:  - 1}}}

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0
3 years ago
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Which of the following will generate a graph that is 3 units to the left of y = x3?
Mamont248 [21]

Answer:

(3) y=(x+3)

Step-by-step explanation:

I'm not sure what is the parent function, but in most graphs if you will shift it to the left or right (negative sign or positive sign, respectively), it will be inside a parenthesis and the opposite sign is the real movement.

For a cubic function these will be the movements:

f(x)=(x+/-h)^3+/-k

Only the opposite sign of h will be the real movement, while k's sign will automatically indicate the correct movement.

h= x-axis movement (horizontal, inside of the parenthesis in the equation)

k= y-axis movement (vertical, outside of the parenthesis in the equation)

Hope it helps

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3 years ago
Sammi has $125.75 in her savings account. She deposits $25.50 into the account each month for the next 6 months.
Rina8888 [55]

Answer:

i think the answer is 278.75

4 0
2 years ago
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