<span>The average rate of change is 3.125 times as fast.</span>
Answer:
153.9380400258yds is the answer
Answer:
70
40 % of 70 is 28
Step-by-step explanation:
Answer:
The outer diameter of the shaft to 2s.f is 12.65cm
Step-by-step explanation:
We know that the expression for the area of a circular cross section is
A=
given data
area of cross section=
bore diameter d= 8cm
from the area of cross section we can solve for the outer diameter D
solving for D we have