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nataly862011 [7]
4 years ago
14

PLEASEEEEEEEEEEE HELP WITH THIS I DONT GET IT

Mathematics
2 answers:
fredd [130]4 years ago
6 0
Ok so draw the outline of the figure than count the squares and the ones that look like triangles are only half of one 
fredd [130]4 years ago
3 0
Draw the Outline and then count how many are at the bottom and multiply that by how tall it is.
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If f(x)=3x2−4x+6 find f(−3)
kvv77 [185]

Answer:

45

Step-by-step explanation:

Replace everything in the equation that has a x to -3:

f(-3)=3(-3)^2-4(-3)+6

Square the -3:

f(-3)=3(9)-4(-3)+6

Multiply/Distribute

f(-3)=27+12+6

Add:

f(-3)=45

Hope this helps!

6 0
3 years ago
Read 2 more answers
A<br> B<br> C<br> D<br> Thanks !!!!!!!!!!
Zarrin [17]

You would multiply the 3w^{2} to every term giving you,

12w^{5}x^{2} + 6w^{4}x + 15w^{3}x^{2}

(Note that when multiplying a squared root number, you add the the exponents together. Also a term/number without an exponent is understood to have a 1 as the exponent, it is just not written)

7 0
3 years ago
What does op =<br><br> 4<br><br> 6<br><br> 8
notsponge [240]

Answer:

6

Step-by-step explanation:

The radius of a circle does not change with direction, it stays constant. This, the radius of the bigger circle is 4, and of the smaller circle is 2. Thus, OP equals 4 + 2 = 6. You're correct! :)

7 0
3 years ago
Read 2 more answers
Using Cramer’s Rule, what is the value of y in the system of linear equations below?
Vadim26 [7]

for the system of equations

a_1x+b_1y=c_1 \\a_2x+b_2y=c_2

the three matrices needed to use Cramer's Rule are:

D=\left[\begin{array}{cc}a_1&b_1\\a_2&b_2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}c_1&b_1\\c_2&b_2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}a_1&c_1\\a_2&c_2\end{array}\right].

To use Cramer's Rule we have to calculate the three determinants listed below of the matrices listed below.

D=\left[\begin{array}{cc}2&5\\-3&-2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}-13&5\\3&-2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}2&-13\\-3&3\end{array}\right] .

The value of the determinants are shown below.

det(D)=(2)(-2)-(-3)(5)=-4+15=11\\det(D_x)=(-13)(-2)-(3)(5)=26-15=11\\det(D_y)=(2)(3)-(-3)(-13)=6-39=-33\\

The value of y is \frac{det(D_y)}{det(D)}=-\frac{33}{11} =-3..

3 0
4 years ago
I have to solve this proportion x+2/4=8/4
Eva8 [605]

Answer:


Step-by-step explanation:

Isolate the x. Note the equal sign, what you do to one side, you do to the other.

Subtract 2/4 from both sides

x + 2/4 (-2/4) = 8/4 (-2/4)j

x = 8/4 - 2/4

Simplify

x = (8 - 2)/4

x = 6/4

Simplify. Change the improper fraction into mixed fraction

x = 6/4 = (4/4 + 2/4) = 1 2/4

1 2/4 simplified = 1 1/2

1 1/2 is your answer

~

5 0
3 years ago
Read 2 more answers
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