9/5 is the answer, hope this helps
Answer:
Attached please find answer
Step-by-step explanation:
= (x² + x - 42) / (x - 6)
= [x² + (7x - 6x) - 42] / (x - 6)
= [x² + 7x - 6x - 42] / (x - 6)
= [(x² + 7x) - (6x + 42)] / (x - 6)
= [x(x + 7) - 6(x + 7)] / (x - 6)
= [(x + 7)(x - 6)] / (x - 6)
= x + 7 → when x approches 6
= 6 + 7
= 13
Other method:
Lim (x² + x - 42) / (x - 6)
x→ 6
When x → 6, there is an indeterminate expression because: 6 - 6 = 0
Do you know the l'Hôpital's rule, when x → a:
Lim [ f(x) / g(x) ] = Lim [ f'(x) / g'(x) ]
f(x) = x² + x - 42
f'(x) = 2x + 1
g(x) = x - 6
g'(x) = 1
= f'(x) / g'(x)
= (2x + 1)/1
= 2x + 1 → when x approches 6
= 12 + 1
= 13
The equation would be:
x≥-4
Answer:
xtp= 4/2
for y- interception subt xTp into equation ytp = 10
<span><em>Partial product </em>multiplication is the process of multiplying the numbers partially (respectively to ones, tens and hundreds) and adding them together in the end. For example, in order to find the product of 3 8 × 6 we should write that,
1) 3 8
× 6
___
4 8
2) 3 8
× 6
_____
4 8
1 8 0
3) 3 8
× 6
______
+ 4 8
1 8 0
______
2 2 8
<em>Regrouping </em>is the multiplication process when we add the partial products to the next tens and hundreds and so on without writing them down. For example, in order to find the product of 3 8 × 6 with the help of regrouping, we write that
4
3 8
× 6
___
228
, where the number 4 above 8 shows the tens of 4 (40), which is going to be added to the tens of the product of 30 times 6. The two processes are the same in a way that you are getting the same result. In the end, it is a multiplication process. The processes differ because of the methods we apply. In partial product multiplication, we break down the number in its ones, tens, hundreds steps and then calculate. However, in regrouping process we consider those steps without breaking them down. </span>
