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3 years ago

13

Last math question.

1 answer:

siniylev [52]3 years ago

5 0

Answer:

<h2>y = 5x + 11</h2>

Step-by-step explanation:

$\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-\text{slope}\\b-\text{y-intercept}\\\\\text{Let}\\\\k:y=m_1x+b_1\\l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\k\ ||\ l\iff m_1=m_2\\=========================$

$\text{We have}\ y=5x+2\to m_1=5\\\\\text{therefore}\ m_2=5.\\\\\text{Put the value of the slope and the coordinates of the given point (-2, 1)}\\\text{to the equation of a line:}\\\\1=5(-2)+b\\1=-10+b\qquad\text{add 10 to both sides}\\1+10=-10+10+b\\11=b\to b=11\\\\\text{Finally:}\\\\y=5x+11$

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Q1) f(x) = 2x^2 - 5x, g(x) 3x^2 find f(2)

pashok25 [27]

Answer:

f(2)= -2

g(2)= 12

Step-by-step explanation:

To solve this we use the substitution method. Since f(2) is your variable, we will plug the x-value of 2 into each equation

f(2)= 2(2)^2-5(2)

f(2)=8-10

f(2)= -2

If the same variable is used for both equations then g(x) would be g(2) as well leaving you with

g(x) = 3x^2

g(2)= 3(2)^2

g(2)=12

6 0

2 years ago

Which nuWhich expressions result in a product that has a best estimate of 80? Select all that apply.

VMariaS [17]

Answer:

E; 8x9 is equal to 72 which estimated is 70

7 0

2 years ago

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Levart [38]

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4 0

2 years ago

Read 2 more answers

Describe how to transform:

Anna71 [15]

Answer:

$x^\frac{35}{6}$

Step-by-step explanation:

The expression to transform is:

$(\sqrt[6]{x^5})^7$

Let's work first on the inside of the parenthesis.

Recall that the n-root of an expression can be written as a fractional exponent of the expression as follows:

$\sqrt[n]{a} = a^{\frac{1}{n}}$

Therefore $\sqrt[6]{a} = a^{\frac{1}{6}}$

Now let's replace $a$ with $x^{5}$ which is the algebraic form we are given inside the 6th root:

$\sqrt[6]{x^5} = (x^5)^{\frac{1}{6}}$

Now use the property that tells us how to proceed when we have "exponent of an exponent":

$(a^n)^m= a^{n*m}$

Therefore we get: $(x^5)^{\frac{1}{6}}=x^{\frac{5}{6}}}$

Finally remember that this expression was raised to the power 7, therefore:

$[tex](\sqrt[6]{x^5})^7=(x^\frac{5}{6})^7=x^\frac{35}{6}$ [/tex]

An use again the property for the exponent of a exponent:

8 0

2 years ago

An animal shelter spends $3.00 per day to care for each cat and $6.50 per day to care for each dog. Amelia noticed that the shel

Ede4ka [16]

Answer:

There were 15 cats at the shelter on Friday.

Step-by-step explanation:

Cost of caring each cat = $3.00

Cost for caring each dog = $6.50

Total money spent by shelter = $84.00

Total Cats and Dogs in the shelter = 21

Let the number of cats in the shelter = k

So, the number of dogs in shelter = 21 -k

Also according to the question:

Total expenditure on cats + total expenditure on dogs = $84.00

or, k ($3.00) + (21-k)($6.50) = $84.00

or, 3k + 136.5 - 6.5 k = 84

or, -3.5 k = 84 - 136.5 = -52.5

⇒3.5 k = 52.5 or k = 52.5/3.5 = 15

⇒ k = 15

Hence, the number of cats in the shelter was 15 on Friday.

7 0

3 years ago