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umka2103 [35]
3 years ago
9

Can anyone help me please? I’ll mark you as a brainliest

Mathematics
2 answers:
drek231 [11]3 years ago
7 0

Answer:

C

Step-by-step explanation:

It is C because if you multiply each number on the left by 250 and then add 500, you will get the number on the right.

4 x 250 = 1000 + 500 = 1500

8 x 250 = 2000 + 500 = 2500

10 x 250 = 2500 + 500 = 3000

13 x 250 = 3250 + 500 = 3750

Yuki888 [10]3 years ago
3 0

Answer:

A

Step-by-step explanation:

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Write a function rule for “The output is 5 less than four times the input.” Use x for the independent variable and y for the dep
Ludmilka [50]

Answer:

y(x) = 4x - 5

Step-by-step explanation:

A dependent variable depends on other factors that are measured . The value of a dependent variable depends on the independent variable. The independent variable stands alone and it does change by the other variable you are trying to measure. Independent variable are usually denoted as x.

The function can be represented below.

y(x) = 4x - 5

x = independent variable

y = dependent variable

y depends on the value of x

5 0
3 years ago
kara needs to get a 75% on her drivers education test in order to get her license. If there are 35 questions, how many does she
marishachu [46]

Answer:

26.25 questions

Step-by-step explanation:

75% of 35 is 26.25

5 0
3 years ago
Read 2 more answers
The question is below
givi [52]
That angle would also be 45
5 0
2 years ago
Read 2 more answers
The diagram shows a 5 cm x 5 cm x 5 cm cube.
mylen [45]

Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

\sqrt{a^2+b^2}

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths a_1, a_2, a_3, \ldots, a_n is

\sqrt{a_1^2 + a_2^2 + a_3^2 + \ldots + a_n^2}

So the solution here is

\sqrt{(5cm)^2 + (5cm)^2 + (5cm)^2} = \sqrt{75cm^2} = 5\sqrt{3cm^2} \approx 5\cdot 1.732cm = 8.66cm

5 0
2 years ago
Read 2 more answers
PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!
pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

  • \cos{\theta} = \pm \frac{2\sqrt{2}}{3}
  • \tan{\theta} = \pm \frac{\sqrt{2}}{4}

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

In this problem, we have that the sine is given by:

\sin{\theta} = \frac{1}{3}

Hence, applying the identity, the cosine is given as follows:

\cos^2{\theta} = 1 - \sin^2{\theta}

\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2

\cos^2{\theta} = 1 - \frac{1}{9}

\cos^2{\theta} = \frac{8}{9}

\cos{\theta} = \pm \sqrt{\frac{8}{9}}

\cos{\theta} = \pm \frac{2\sqrt{2}}{3}

The tangent is given by the sine divided by the cosine, hence:

\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}

\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}

\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}

\tan{\theta} = \pm \frac{\sqrt{2}}{4}

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0
2 years ago
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