Answer: Ix - 65°F I ≤ 5°F.
Where the solutions of this equation are the set of possible temperatures that we can have.
Step-by-step explanation:
We know that the mean temperature is 65°F.
And it may be 5°F colder or warmer.
Then the minimum temperature is 65°F - 5°F = 60°F
The maximum temperature is 65°F + 5°F = 70°F
Then the range of possible temperatures is [60°F, 70°F]
Now we can model this with an absolute value equation.
Now we have:
the mean, M = 65°
Half the difference between maximum and minimum:
d = (70°F - 60°F)/2 = 5°F.
Now we can write the absolute equation:
I x - M I ≤ d
Where x represents the possible temperatures that we can have
in this case are:
Ix - 65°F I ≤ 5°F.
E^(xy) = 2
(xdy/dx + y)e^(xy) = 0
At point (1, ln2), dy/dx + ln2 = 0
dy/dx = -ln2
Answer:
Width =9 cm
Length =6 cm
Step-by-step explanation:
Let x be width, then length is x − 3
Let area be E. Then we have: E = x ⋅ (x −3)
54= x^2-3x
x^2-3x-54=0
We then do the Discriminant of the equation:
D=9+216
D=225
X1=3+15 over 2. which is 9
X2= 3-15. over 2. which is -6 Which is declined, since we can't have negative width and length.
Therefore x is 9. So width
So width = x = 9cm and length is x-3 = 9-3cm=6 cm
