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Aleks04 [339]
3 years ago
10

what acceleration does the force of earth's gravity produceit varies depending on how long it has been falling.it changes direct

ion every 9.8 meters9.8 m/s/sgravity does not produce an acceleration
Physics
1 answer:
iren2701 [21]3 years ago
3 0
If gravity is the ONLY force acting on an object, then the force of
Earth's gravity produces acceleration of 9.8 meters per second²
downward.  That number doesn't change, and it doesn't depend
on the mass or weight of the object.

If there are any other forces acting on the object at the same time,
like air resistance or some other kind of friction for example, then
all bets are off, and we can't say what the object's acceleration will
be in that case.
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The average speed and kinetic energy of the particles in a gas are proportional to the measured what of the gas
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Answer: Temperature

Explanation:

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In which of the following scenarios is the total momentum of the system conserved?
leonid [27]

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The total momentum of a system is conserved only when the system is closed.

Explanation:

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An object 2.7 cmtall is placed12 cmin front of a mirror. •What type of mirror and what radius of curvature are needed to createa
nasty-shy [4]

Answer:

a. Concave mirror, radius of curvature = 16 cm b. magnification = 2

Explanation:

a. Since the image is upright and larger than the object, we need a concave mirror.

We know image height, h'/object height, h = -image distance, d'/object distance, d

h'/h = -d'/d

Using the real is positive convention,

h'= + 5.4 cm, h = + 2.7 cm and d = + 12 cm.

So, + 5.4 cm/+ 2.7 cm = -d'/+ 12 cm

2 = -d'/12

d' = -2 × 12 cm

= -24 cm

Using the mirror formula 1/d + 1/d' = 2/r where r = radius of curvature of the mirror

1/+12 + 1/- 24 = 2/r

1/12(1 - 1/2) = 2/r

1/12(1/2) = 2/r

1/24 = 2/r

r/2 = 24

r = 2 × 24

r = 48 cm

b.

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3 0
3 years ago
At what height must a 6-kilogram object be placed to have 12 joules of
Serga [27]

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0.2m

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4 0
4 years ago
A rocket initially at rest accelerates at a rate of 99.0 meters/second ^2.Calculate the distance covered by the rocket if it. At
Pani-rosa [81]

The distance covered is 1000 m

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The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

s=vt-\frac{1}{2}at^2

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v is the final velocity

t is the time

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For the rocket in this problem, we have:

v = 445 m/s is the final velocity

a=99.0 m/s^2 is the acceleration

t = 4.50 s is the time

Substituting, we find the distance covered:

s=(445)(4.50)-\frac{1}{2}(99.0)(4.50)^2=1000 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

8 0
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