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Vlad [161]
3 years ago
11

Which statements about a sample of gas containing molecules of different masses are true?

Physics
1 answer:
Alexxandr [17]3 years ago
6 0

Answer:

More-massive gas molecules in the sample have lower rms speed than less-massive ones.

Explanation:

The rms speed is defined as the prediction that how fast the molecule travel at a given temperature.

Mathematically, rms speed can be written as,

v_{rms} =\sqrt{\frac{3RT}{M} }

Here, T is the temperature, M is the mass of gas molecule.

Now from this it is clearly seen that rms speed is inversely related with mass of the gas molecule.

Therefore, gas molecule which posses more mass in the sample have smaller rms speed than less-massive ones.

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A uniform narrow tube 1.90 m long is open at both ends. It resonates at two successive harmonics of frequencies 280 Hz and 294 H
Over [174]

Answer:

a)14Hz

b)26.6m/s

Explanation:

a)we were given

the first harmonics frequencies as 280 Hz

The second harmonic frequency as 294 Hz.

The fundamental frequency is equal to the gap which means the distance that exist between the harmonics, then

the fundamental frequency=(294 - 280 = 10 Hz)

= 14Hz

b) We know the frequency and the wavelength of the sound wave (

We were told that the wavelength must be twice the length of the tube then, velocity can be calculated as

And fundamental frequency= 14Hz, and distance of 1.90 m then

v = f*2L = (14Hz)*2*(1.90 m) = 26.6m/s

Therefore, the speed of sound in the gas in the tubes is 26.6m/s

7 0
3 years ago
1. Take the speed at which the body moves as 10 m/s 2. Calculate the distance travelled by the body every second 3. Take the tim
exis [7]

Answer:

a)this graph is also a line     b) in both cases we have a uniform movement

Explanation:

In this exercise we have a uniform movement

     v = d / t

     d = v t

in the table we give some values ​​to make the graph

       t (s)    d (m)

        1         10

        2        20

        3         30

In the attached we can see the graph that is a straight line

we have another vehicle at v = 50 me / S

t (s)     d (m)

1         50

2        100

3         150

this graph is also a line

b) in both cases we have a uniform movement

3 0
4 years ago
amelia goes for mountering with some selected friend of her batch .Intially she is scared of it .Her trainer John tells her that
IRISSAK [1]

Answer:

나쁜 소식 원인 나는 ques 원인 메신저 한국어 내가 캔트 unfmder 대답 할 수 없습니

5 0
3 years ago
A 0.83-kg block is hung from and stretches a spring that is attached to the ceiling. A second block is attached to the first one
vodomira [7]

Answer:

1.66 kg

Explanation:

Given that a 0.83-kg block is hung from and stretches a spring that is attached to the ceiling.

From Hook's law

F = Ke

But F = mg

Substitute mg for force in the Hook's law

Mg = ke

0.83 × 9.8 = ke

Make K the subject of formula

8.134 = Ke

K = 8.134 /e

Given that a second block is attached to the first one, and the amount that the spring stretches from its unstretched length triples.

That is

(0.83 + M) × 9.8 = K (3e)

Substitutes K into the above equation

(0.83 + M) × 9.8 = 8.134 / e (3e)

The e will cancel out

(0.83 + M) × 9.8 = 24.402

0.83 + M = 24.402/9.8

0.83 + M = 2.49

M = 2.49 - 0.83

M = 1.66 kg

Therefore, the mass of the second block is 1.66kg

6 0
3 years ago
A volleyball player bumps a ball across a net with the velocity and angle shown below. What is the maximum height of the ball?
Marrrta [24]

Answer:

D. 12.4 m

Explanation:

Given that,

The initial velocity of the ball, u = 18 m/s

The angle at which the ball is projected, θ = 60°

The maximum height of the ball is given by the formula

                             h = u² sin²θ/2g  m

Where,

                           g - acceleration due to gravity. (9.8 m/s)

Substituting the values in the above equation

                            h = 18² · sin²60 / 2 x 9.8

                               = 18² x 0.75 / 2 x 9.8

                               = 12.4 m

Hence, the maximum height of the ball attained, h = 12.4 m

6 0
4 years ago
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