Answer:
yes I do
Step-by-step explanation:
can you help me with my question In the extended simile of the underlined passage from Paragraph 15 of "A Wagner Matinee," the narrator makes an observation about the soul that aring rokol been A. it is like a strange moss on a dusty shelf that, with excruciating suffering, can wither and die y for I the be B though after excruciating suffering it may seem to wither, the soul never dies, C. excruciating, interminable suffering that goes on for half a century can kill the soul.
(3x86)+(9,538+629) = 10,425
Hope this helps
Solution :
Let x be student will be left handed
P = 0.09
Using the normal approximation to binomial distribution,
a). n = 108,
μ = np = 9.72
![$\sigma = \sqrt{np(1-p)}$](https://tex.z-dn.net/?f=%24%5Csigma%20%3D%20%5Csqrt%7Bnp%281-p%29%7D%24)
![$=\sqrt{8.8452}$](https://tex.z-dn.net/?f=%24%3D%5Csqrt%7B8.8452%7D%24)
= 2.9741
Required probability,
P(x=8) = P(7.5 < x < 8.5)
![$=P\left(\frac{7.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{8.5-9.72}{2.9741}\right)$](https://tex.z-dn.net/?f=%24%3DP%5Cleft%28%5Cfrac%7B7.5-9.72%7D%7B2.9741%7D%3C%20%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3C%20%5Cfrac%7B8.5-9.72%7D%7B2.9741%7D%5Cright%29%24)
![$=P(-0.75 < z < -0.41)$](https://tex.z-dn.net/?f=%24%3DP%28-0.75%20%3C%20z%20%3C%20-0.41%29%24)
Using z table,
= P(z<-0.41)-P(z<-0.75)
= 0.3409-0.2266
= 0.1143
b). P(x=12) = P(11.5 < x < 12.5)
![$=P\left(\frac{11.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{12.5-9.72}{2.9741}\right)$](https://tex.z-dn.net/?f=%24%3DP%5Cleft%28%5Cfrac%7B11.5-9.72%7D%7B2.9741%7D%3C%20%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3C%20%5Cfrac%7B12.5-9.72%7D%7B2.9741%7D%5Cright%29%24)
![$=P(0.60 < z < 0.94)$](https://tex.z-dn.net/?f=%24%3DP%280.60%20%3C%20z%20%3C%200.94%29%24)
Using z table,
= P(z< 0.94)-P(z< 0.60)
= 0.8294 - 0.7257
= 0.1006
The answer to your problem that you are stuck on is 4 which is the third option