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3 years ago

Hi here is the problem

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

3 0

Answer:

Look at the image.

Step-by-step explanation:

24 ÷ 4 = 6

6 × 9 = 54

24 ÷ 3 = 8

8 × 5 = 40

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The length of a jogging trail is 3528 m. A jogger wants to complete the trail within 30 min.

lbvjy [14]

Answer:

117.6 meter per min

Step-by-step explanation:

since the jogger wants to complete the trail in 30 minutes and the total length of the trail is 3528m you just need to divide the length of the trail (3528) by the total amount of time to get the answer

7 0

3 years ago

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The gas mileage for a certain model of car is known to have a standard deviation of 6 mi/gallon. A simple random sample of 49 ca

lord [1]

Answer:

The answer is "(27.030,29.770)"

Step-by-step explanation:

$(\bar{x}) = 28.4$

$(n)= 49$

$(\sigma) = 6$

$(CI) = \bar{x}\pm z^*_{\frac{\alpha}{2}} \frac{\sigma}{\sqrt{n}}$

$z^*_{\frac{\alpha}{2}}\ for \ 89\%\ confidence = 1.598 \\\\\text{Using z table }\\\\ NORM.S.INV(1-\frac{(1-0.89)}{2})$

$CI = 28.4 \pm 1.598 \times \frac{6}{\sqrt{49}}=(27.030,29.770)$

8 0

3 years ago

Which of the following mixed numbers is equivalent to 12.1 6 ?

Sliva [168]

Well, you don't have any options.
But a mixed number for 12.16 would be 12 4/25. Hope it helps! :)

7 0

3 years ago

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What is the slope of the graph shown?

astra-53 [7]

Slope is going down so it’s gonna be y=6x+2

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3 years ago

Certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours. Find the probabi

Anna71 [15]

Answer:

Step-by-step explanation:

given that certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours.

Sample size n =16

Std error of sample mean = $\frac{\sigma}{\sqrt{n} } \\= 15$

x bar follows N(800, 15)

the probability that a random sample of 16 tubes taken from the group will have a mean lifetime

(a) between 790 and 810 hours,

= $P(790$

(b) less than 785 hours

$=P(X$

, (c) more than 820 hours,

$=P(X>820)\\=p(Z>1.333)\\= 0.0913$

(d) between 770 and 830 hours

= $P(|Z|$

4 0

3 years ago