An institute reported that 62?% of its members indicate that lack of ethical culture within financial firms has contributed most
to the lack of trust in the financial industry. Suppose that you select a sample of 100 institute members. Complete parts ?(a) through ?(d) below.a) What is the probability that the sample percentage indicating that lack of ethical culture within financial firms has contributed the most to the lack of trust in the financial industry will be between 62% and 67%b. The probability is 80?% that the sample percentage will be contained within what symmetrical limits of the population? percentage?
The probability is 80?% that the sample percentage will be contained above ___?% and below ___?%.
c. The probability is 91?% that the sample percentage will be contained within what symmetrical limits of the population? percentage?
The probability is 91?% that the sample percentage will be contained above _____% and below _____?%.
d. Suppose you selected a sample of 400 institute members. How does this change your answers in ?(a) through
?(c)??
The probability is 80?% that the sample percentage will be contained above ___?% and below ___?%.
c. The probability is 91?% that the sample percentage will be contained within what symmetrical limits of the population? percentage?
The probability is 91?% that the sample percentage will be contained above _____% and below _____?%.
d. Suppose you selected a sample of 400 institute members. How does this change your answers in ?(a) through
?(c)??
1 answer:
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1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that , so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:
Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹
Answer:
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Step-by-step explanation:
This is where your <em>median</em> is near the lower quartile.
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