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4 years ago

Given m ZLMN = 145°, what is m ZXMN? Show all relevant work.

Mathematics

1 answer:

myrzilka [38]4 years ago

4 0

80 degrees. 145 = (4x+5) + (6x-10) = 10x-5... so 10x = 150, x = 15. LMN = 6x-10 = 6(15) - 10 = 80.

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The profits of a company are found by subtracting the company's costs from its revenue. If a company's cost can be modeled by 14

evablogger [386]

Answer:

$-0.0002x^2 +26x-120000$

Step-by-step explanation:

The correct question should be:

We have been told that all we have to do to get profit is to subtract the cost from revenue.

Revenue = $40x - 0.0002x^2$

Cost <em>= </em> $14x + 120,000$ <em />

<em />

Hence:

Profit = $40x - 0.0002x^2 - (14x + 120000)$

$40x - 0.0002x^2 - 14x - 120000\\\\40x - 14x - 0.0002x^2 - 120000\\\\26x - 0.0002x^2 - 120000$

Putting it in ordered form:

$-0.0002x^2 +26x-120000$

This is an expression for the profit.

4 0

3 years ago

Waygon bought a new fishing pole on sale for $33 he saved $9 what was the original price

antoniya [11.8K]

42 dollars is your answer

4 0

3 years ago

An equation is shown below:

Drupady [299]

27x - 144 + 15 = 6x - 24
27x - 129 = 6x - 24
+129 +129
--------- --------
0 105
27x = 6x + 105
-6x -6x
----- ------
21x 0

21x = 105

21x/21 = 105/21

x = 5

Remove brackets
Gather like terms
Get rid of the lone number
Transfer
Divide

Hope this helps :)

4 0

3 years ago

Which is the same as 9/5?

Vesnalui [34]

Answer:

9 divided by 5 is the same as 9/5

7 0

3 years ago

Read 2 more answers

Based on aâ poll, among adults who regret gettingâ tattoos, 18â% say that they were too young when they got their tattoos. Assum

Sergeeva-Olga [200]

Answer:

a) 20.44% probability that none of the selected adults say that they were too young to get tattoos.

b) 35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c) 56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d) No

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they say they were too young when they got their tattoos, or they don't say that. Each adult is independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

18% say that they were too young when they got their tattoos.

This means that $p = 0.18$

Eight adults who regret getting tattoos are randomly selected

This means that $n = 8$

a. Find the probability that none of the selected adults say that they were too young to get tattoos.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{8,0}.(0.18)^{0}.(0.82)^{8} = 0.2044$

20.44% probability that none of the selected adults say that they were too young to get tattoos.

b. Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{8,1}.(0.18)^{1}.(0.82)^{7} = 0.3590$

35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c. Find the probability that the number of selected adults saying they were too young is 0 or 1.

Either a. or b.

20.44 + 35.90 = 56.34

56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d. It we randomly select 9 adults. Is 1 a significantly low number who day that they were too young to get tattoos?

Now $n = 9$

It is significantly low if it is more than 2.5 standard deviations below the mean.

The mean is $E(X) = np = 9*0.18 = 1.62$

The standard deviation is $\sqrt{V(X)} = \sqrt{n*p*(1-p)} = \sqrt{9*0.18*0.82} = 1.15$

1 > (1.62 - 2.5*1.15)

So the answer is no.

5 0

3 years ago