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Pepsi [2]
3 years ago
11

Which expression demonstrates the use of the commutative property of addition in the first step of simplifying the expression (–

3 + i) + (18 + 5i)?
Mathematics
1 answer:
madam [21]3 years ago
4 0
The first step of simplifying the expression would be summing up the "i"s. They are separate ("+i" and "+5i") but you can still sum them up though they are apart. This is thanks to the commutative property of addition which allows summing the terms of an expression with several additions in whatever order it is prefered. Commutative means that the terms can be interchangeable. 
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How do i do this problem 0.25(x+4)-3=28
KiRa [710]
Distribute the .25 to get .25x + 1 - 3 = 28

Then simplify to get .25x - 2 = 28

Move the two to the right to get .25x = 30

Then divide to leave x: 30 / .25 = 120

X = 120
6 0
3 years ago
Read 2 more answers
Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}


                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

7 0
3 years ago
Factor 4x^2+28x-32=0
Luda [366]
Let's solve your equation step-by-step.
<span><span><span><span>4<span>x^2</span></span>+<span>28x</span></span>−32</span>=0
</span>Step 1: Factor left side of equation.
<span><span><span>4<span>(<span>x−1</span>)</span></span><span>(<span>x+8</span>)</span></span>=0
</span>Step 2: Set factors equal to 0.
<span><span><span>x−1</span>=<span><span><span>0<span> or </span></span>x</span>+8</span></span>=0
</span><span><span>x=<span><span>1<span> or </span></span>x</span></span>=<span>−<span>8</span></span></span>
8 0
3 years ago
Read 2 more answers
Ma=np,for a is what<br>​
Julli [10]

Answer:

\displaystyle \frac{np}{m} = a

Step-by-step explanation:

You divide both sides by <em>m</em><em> </em>to get the above answer:

\displaystyle \frac{ma}{m} = \frac{np}{m} \\ \\ a = \frac{np}{m}

I am joyous to assist you anytime.

8 0
3 years ago
A bacteria culture grows with constant relative growth rate. The bacteria count was 1,920 after 4 hours and 1,966,080 after 12 h
attashe74 [19]

From the calculation, the growth rate is 0.88.

<h3>What is the growth rate?</h3>

To find the relative growth rate

P1 = Poe^rt

P2 = Poe^rt

Thus;

1920 = Poe^4r ------ (1)

1966080 =Poe^12r -------(2)

P2/P1 gives;

1966080/1920 = Poe^12r/Poe^4r

1024 = e^12r/e^4r

1024 =e^8r

1024 = (e^r)^8

2^10 = (e^r)^8

e^r = 2^1.25

e^r = 2.38

r = ln(2.38)

r = 0.88

The initial size of the culture is;

1920 = Poe^(0.88 * 4)

Po = 1920/e^(0.88 * 4)

Po = 57

The  expression for the exact number of bacteria after t hours is

P(t) = 57e^0.08t

The growth (in bacteria per hour) after 9.5 hours is

P(t) = 57e^(0.88 * 9.5)

P(t) = 243544

For the number to reach 72,000;

72,000 =  57e^0.88t

72,000/57 = e^0.88t

ln 126 = ln[e^0.88t]

4.8 = 0.88t

t = 4.8/0.88

t = 5.5 hours

Learn more about exponential growth;brainly.com/question/13674608

#SPJ1

8 0
2 years ago
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