Answer:
I got 4e+12 which is d
I think
Step-by-step explanation:
Answer:
Not
Step-by-step explanation:
In this case, the degree of variable y is 1 , the degrees of the variables in the equation violate the linear equation definition, which means that the equation is not a linear equation.
Answer: 3/10
Step-by-step explanation:
Take the derivative of
to get
. Set that equal to 0 to find the critical points of the function. The critical points is when the slope is either 0 or undefined.
Now do:
![20x-6=0\\20x=6\\x=\frac{6}{20} = \frac{3}{10}](https://tex.z-dn.net/?f=20x-6%3D0%5C%5C20x%3D6%5C%5Cx%3D%5Cfrac%7B6%7D%7B20%7D%20%3D%20%5Cfrac%7B3%7D%7B10%7D)
There are quite a few more steps to actually find the minimum, but for this example you can automatically assume its a minimum because it is the only critical point of the function. Ill show you these extra steps tho.
Plug in two numbers into the derivative. One that is less than 3/10 and one that is greater than 3/10. The numbers 0 and 1 are fine. When x = 0, the function is -6. When x = 1, the function is +14. A switch from negative to positive indicates a minimum value
we know that
In the graph the intersection both functions is the point when f(x)=g(x)
so
see the graph
the point of intersection both graphs is ![(1.5,2)](https://tex.z-dn.net/?f=%281.5%2C2%29)
that means
for the input value of ![x=1.5](https://tex.z-dn.net/?f=x%3D1.5)
![f(1.5)=g(1.5)=2](https://tex.z-dn.net/?f=f%281.5%29%3Dg%281.5%29%3D2)
therefore
<u>the answer is</u>
the input value is ![x=1.5](https://tex.z-dn.net/?f=x%3D1.5)