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Vesna [10]
3 years ago
14

A box shaped like a rectangular prism has a height of 17 in and a volume of 2,720 in³ The length is 4 inches greater than twice

the width. What is the width of the box?
–10 in 8 in (my answer???) 20 in 40 in *
Mathematics
1 answer:
wolverine [178]3 years ago
6 0
Width --- x 
<span>length --- 2x+4 </span>

<span>(17)(x)(2x+4) = 2720 </span>
<span>x(2x+4) = 160 </span>
<span>2x^2 + 4x - 160=0 </span>
<span>x^2 + 2x - 80 = 0 </span>
<span>(x+10)(x-8) = 0 </span>
<span>x = -10 , which would make no sense </span>
<span>or </span>
<span>x = 8 </span>
<span>The box is 8 inches wide </span>


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How many square feet of outdoor carpet will we need for this hole?​
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MY WORK:

First, you would cut it up into different parts/shapes

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Then, you would find the area of each.

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Lastly, you would add!

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7 0
3 years ago
The Reyes want grilled chicken and tilapia for dinner. Mrs.
seropon [69]

Answer:

Kilogram of chicken = 1

Kilogram of tilapia = 3

Step-by-step explanation:

Cost of chicken = 150 per kilo

Cost of tilapia = 100 per kilo

Number of kilos of each if total cost should not exceed 450

Let :

Number of kilo of chicken = x

Number of tilapia kilo = y

The constraint :

150x + 100y ≤ 450

We could choose some reasonable values of x and y then, test the constraint ;

If x = 1 and y = 3

150(1) + 100(3) = 450

Hence,

1 kilo of chicken with 3 kilos of tilapia offers the greatest combination of Number of kilograms of tilapia and chicken that could be purchased and still satisfy the maximum cost constraint.

6 0
3 years ago
Dylan plans to eat 1/5 of his candy bar. his 4 friends want him to share the rest equally. show how dylan and his friends can ea
allsm [11]
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7 0
3 years ago
The manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour. (a-1) At α = .05 i
ioda

Answer:

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given sample size 'n' =16

Given the manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour.

mean of the Population 'μ' = 560

Mean of the sample Χ⁻ = 538

sample standard deviation' S' = 50

<em><u>Null hypothesis</u></em><em>:H₀:μ > 560</em>

<em><u>Alternative Hypothesis</u></em><em>:H₁ : :μ < 560 (left tailed test)</em>

<em>Test statistic</em>

   t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }

  t = \frac{538-560 }{\frac{50}{\sqrt{16} } } = -1.76

|t| = |-1.76| = 1.76

<em>Degrees of freedom </em>

<em>γ = n-1 =16-1 =15</em>

t_{\frac{\alpha }{2} } = t_{\frac{0.05}{2} } =t_{0.025} =2.131

<em><u>Conclusion</u></em>:-

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

6 0
4 years ago
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