A) Has two horizontal asymptotes. One at y = −1 and one at y = <span>1
B) </span><span>B has a asymptote at y = 0</span><span>
</span><span>
C) </span> Does have two horizontal asymptotes. One at y = 1 and y = −1
The given coordinates are:
p1: (12,4) and p2: (-8,8)
Th x coordinate of the midpoint is calculated as follows:
Xmidpoint = (x1+x2) / 2 = (12+-8) / 2 = 4/2 = 2
The y coordinate of the midpoint is calculated as follows:
Ymidpoint = (y1+y2) / 2 = (4+8) / 2 = 12/2 = 6
Based on the above calculations, the midpoint of the segment with the given coordinates is (2,6)
the correct answer would be:
A) (x, y) → ( x + 1, y + 2); (−2, 6)
Number 4 is 150 cm cubed
number 5 is 328 cm cubed