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saveliy_v [14]
3 years ago
12

WILL MARK BRAINLIEST IF CORRECT

Mathematics
2 answers:
slamgirl [31]3 years ago
7 0
The answer is y = 4x because it is linear programming

Because x = 1 y= 4 which helps you determine the gradient
Mrrafil [7]3 years ago
4 0

Answer: C

Step-by-step explanation:

The x times 4 equals the y in each column.

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I need help ASAP pls help me!!:/
Olin [163]

Answer:

if i am right it yes yes no

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
What is x solve the equation <br>a(x + b)-C=d​
Nadya [2.5K]

Answer:

x = d/ a + c / a - b

Step-by-step explanation:

a( x + b ) - c = d

add c on both sides

a( x + b) = d + c

ax + ab = d + c

subtract ab from both sides

ax = d + c - ab divide both sides by a

ax / a = d/ a + c/ a - ab / a

x = d/ a + c / a - b

6 0
3 years ago
What is the image of point (4, 3) if the rotation is -270º ?
Ludmilka [50]

Answer:

OK so you point is y=4 and x=3 so plot that on a x,y graph. Then to turn it -270 degrees you need to clock wise. normally you would just go counter clock wise but since your rotation is negative you go counter clock wise. hope this helped!!

Step-by-step explanation:

3 0
3 years ago
Please Help! Will Give Brainlest!
ella [17]

Answer:

2

Step-by-step explanation:

amplitude = distance from undisturbed position/centre line to trough or peak

8 0
2 years ago
Read 2 more answers
Two cross roads, each of width Sm, run at right angles through the
Ray Of Light [21]

Answer:

Rs 57750

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

​

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

7 0
2 years ago
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