$area\ of\ floor\ : A= 8500\ in^2\\\\Tiles:6\ in\ x\ 13\ in\\\\Area\ of\ one\ tile:\\\\A_t=6*13=78\ in^2\\\\Number\ of\ tiles:\ \frac{A}{A_t}=\frac{8500}{78}=108,9\approx109\\\\He\ will\ need\ 109\ tiles.$

7 0

3 years ago

Somebody help me on A. And. B. Pleaseeee

irakobra [83]

Answer:

a. dbc = 66, ABC = 132

b. abd = 52, dbc= 52

Step-by-step explanation:

just remember that bisects means that the angles on either side of the middle line are equal. so for a, dbc = abd and ABC = 2x 66

for b, abd and dbc are equal, so both of them are just 104 divide by two

6 0

3 years ago

The product of 6 less than a number and 4 more than the<br> number

Lorico [155]

Answer:

(x-4)(x+8)

Step-by-step explanation:

8 0

3 years ago