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soldier1979 [14.2K]
3 years ago
13

Which expression has the same meaning as p 11/5?

Mathematics
1 answer:
Setler [38]3 years ago
3 0
You answer is ^5rat p^11 it will look that that

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Solve this system of linear equations. Separate
AleksAgata [21]
  • 7x=-63-11y-(1)
  • 8x=93+11y--(2)

Adding both

  • 15x=30
  • x=2

Putting in second one

  • 8(2)=93+11y
  • 11y=16-93
  • 11y=-77
  • y=-7
5 0
1 year ago
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This table gives a few (x,y) pairs of a line in the coordinate plane.
Anna11 [10]

Answer:0,4

I hope this helps, all i did was put the table into a website that made it into a equation then put that equation into desmos and it showed the y intercept of the line.

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2 years ago
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Mario took clothes to the cleaners three times last month. first, he brought 3 shorts and 1pair of slacks and $10.96. then, he b
valina [46]

Let us say that:

x = cost of shorts

y = cost of slacks

z = cost of sports coat

 

From the given statements, we can create the following equations:

eqtn 1: 3 x + y = 10.96

eqtn 2:  7 x + 2 y + z = 30.40

eqtn 3:  4 x + z = 14.45

 

Rewrite eqtn 1 explicit to y:

y = 10.96 – 3 x                    --> eqtn 4

 

Rewrite eqtn 3 explicit to z:

z = 14.45 – 4x                     --> eqtn 5

 

Plug in the values of y (eqtn 4) and z (eqtn 5) to eqtn 2:

7 x + 2 (10.96 – 3 x) + 14.45 – 4 x = 30.40

7 x + 21.92 – 6 x + 14.45 – 4 x = 30.40

- 3 x + 36.37 = 30.40

- 3 x = - 5.97

x = 1.99

 

Eqtn 4:

y = 10.96 – 3 x   

y = 10.96 – 3 (1.99)

y = 4.99

 

Eqtn 5:

z = 14.45 – 4x

z = 14.45 – 4 (1.99)

z = 6.49

 

 

Therefore each shirt cost $1.99, each slacks cost $4.99, and each sports coat cost $6.49.

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7 0
3 years ago
What budget item does NOT necessarily include monthly expenses? A.transportation
xeze [42]
Medical expenses aren't necessarily a monthly expense since many people are healthy and therefore don't require this on a monthly basis.

6 0
3 years ago
What’s the correct answer for this?
Phantasy [73]

Answer:

first option

Step-by-step explanation:

Given 2 secants to a circle from an external point, then

The product of the external part and the whole of one secant is equal to the external part and the whole of the other secant, that is

PQ(RP) = PS(TP)

5 0
2 years ago
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