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Fiesta28 [93]
3 years ago
10

A piece of wire measuring 20 feet is attached to a telephone pole as a guy wire. The distance along the ground from the bottom o

f the pole to the end of the wire is 4 feet greater than the height where the wire is attached to the pole how far up the pole does the guy wire reach? PLEASE SHOW ALL WORK !!!!

Mathematics
1 answer:
dem82 [27]3 years ago
8 0

Answer: Height at which the wire is attached to the pole is 12 feet.

Explanation:

Since we have given that

Length of the wire = 20 feet

Let the height at which wire is attached to the pole be h

and distance along the ground from the bottom of the pole to the end of the wire be x+4

Now, it forms  a right angle triangle so, we can apply "Pythagorus theorem".

H^2=B^2+P^2\\\\20^2=x^2+(x+4)^2\\\\400=x^2+x^2+8x+16\\\\400=2x^2+8x+16\\\\400=2(x^2+4x+8)\\\\200=x^2+4x+8\\\\x^2+4x-192=0\\\\x^2+16x-12x-192=0\\\\x(x+16)-12(x+16)=0\\\\(x+16)(x-12)=0\\\\x=-16\ and\ 12

But height cant be negative so, height will be 12 feet.

Hence, height at which the wire is attached to the pole is 12 feet.


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Recall the formula for finding the area of a rectangle:

           Area = Length × Width

Recall the formula for finding the perimeter of a rectangle:

         Perimeter = 2 ( Length + Width )

Given in your problem:
        Area = 40 sq. units
        Perimeter = 26 units

Required to solve for:
        Length (L) and width (W)

• First, substitute the given to the formula:

        Area = Length x Width
          40 = L × W      ⇒   equation number 1

       Perimeter = 2 ( Length + Width )
            26 = 2 ( L + W )     ⇒   equation number 2


• Simplifying equation number 2,
           13 = L + W

 • Rearranging the equation, 

         L = 13 - W   ⇒   equation 3

Substituting equation 3 from equation 1:

      ( equation 1 )               40 = (L)(W)
      ( equation 3 )                L = 13 - W
                                      40 = (13 - W) (W)
                                      40 = 13W - W² 
      ( regrouping )          W² - 13W + 40 = 0
      ( factoring )             (W - 8) (W - 5) = 0
                                     W - 8 = 0    ;     W - 5 = 0
                                        W = 8      ;        W = 5
   
Therefore, there are 2 possible values for the width of the rectangle. It can be 8 units or 5 units.

• Now to solve for the length of the rectangle, substitute the two values of width to equation 3.

      (equation 3)        L = 13 - W
                       for W = 8    ⇒   L = 13 - 8
                                                   L = 5 units
                   
                       for W = 5    ⇒  L = 13 - 5
                                                   L = 8 units

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3 years ago
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