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puteri [66]
3 years ago
12

If Callum is consuming his utility maximizing bundle and the price of one good rises, what happens to the marginal utility per d

ollar spent on this good (MU/P), and what should Callum do?
Mathematics
1 answer:
monitta3 years ago
8 0

Answer:

MU/P has decreased and Callum should buy less of the good.

Step-by-step explanation:

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Can someone help me with these 2?
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3 years ago
HELP! WILL GIVE BRAINLIEST!! EASY! GIVE LONG DETAILED ANSWER!
OLEGan [10]

Answer:

x² + 2x + y² + 4y = 20

(x² + 2x + 1) - 1 + (y² + 4y + 4) - 4 = 20

(x + 2)² + (y + 4)² - 5 = 20

(x + 2)² + (y + 4)² = 25

Therefore, the center is (-2, -4) and the radius is √25 = 5.

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3 years ago
Simplify using the distributive property, Show all work -2(x - 5) + 4(9 + x).
zzz [600]
-2(x - 5) + 4(9 + x)
-2x + 10 + 36 + 4x
=2x + 46
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3 years ago
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Lana71 [14]

Answer:

Step-by-step explanation

(8 * 10) + ( 2 * \frac{1}{100} ) + ( 9 * \frac{1}{1000} )

⇒ 80 + ( 2 * 0.01 ) + ( 9 * 0.001 )

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3 years ago
Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States. In Australia, only 1.5% of
Umnica [9.8K]

Answer:

a. X is a binomial random variable with n = 50 and p = 0.04

b. Y is a binomial random variable with n = 40 and p = 0.015

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

X: the number of US residents (out of 50) with blood type AB.

Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States

This means that p = 0.04, n = 50

Y: the number of Australians (out of 40) with blood type AB.

In Australia, only 1.5% of the population has blood type AB.

This means that p = 0.015, n = 40

Z: the total number of individuals (out of 90) with blood type AB.

Here

n = 90, p = 0.04*\frac{50}{90} + 0.015*\frac{40}{90} = 0.0289

Which of the following is true about the random variables X, Y, and Z?

Options a and b are true, while c is false.

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