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4 years ago

How do I solve this complex expression- (5+2i)+(6i^2-3i+2)

Mathematics

1 answer:

Anettt [7]4 years ago

6 0

Answer:

1-i

Step-by-step explanation:

Hello,

you know that $i^2=-1$ , right?

$(5+2i)+(6i^2-3i+2)\\\\=5+2i-6-3i+2\\ \\=1-i$

Thanks

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3 years ago

Throughout Lewis Carroll's book, Alice's Adventures in Wonderland, Alice's size changes. Her normal height is about 50 inches ta

alexandr402 [8]

Answer:

The answer is 75 inches.

Step-by-step explanation:

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3 years ago

What happens when Jonah is thrown into the sea?

Licemer1 [7]

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4 years ago

Read 2 more answers

If a +2b+6c=-9 what is 12c+2a+4b

uranmaximum [27]

A + 2b + 6c = -9
Multiply the equation by 2,
2a + 4b + 12c = -18

In short, Your Answer would be -18

Hope this helps!

5 0

3 years ago

Will give brainliest, please help fast

Gekata [30.6K]

Answer:

Converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

Step-by-step explanation:

we are given quadratic equation: $x^2-20x+13=0$

And we need to convert it into completing the square method.

Completing the square method is of form: $a^2-2ab+b^2=(a-b)^2$

Looking at the given equation $x^2-20x+13=0$

We have a = x

then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20

So, 20x in form of 2ab can be written as: 2(x)(10)

So, we need to add and subtract (10)^2 on both sides

$x^2-20x+13=0\\x^2-2(x)(10)+(10)^2-(10)^2+13=0\\(x^2-2(x)(10)+(10)^2) \:can\: be\: written\: as\: (x-10)^2 \\(x-10)^2-100+13=0\\(x-10)^2-87=0\\(x-10)^2=87$

So, converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

4 0

3 years ago