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2 years ago

What's the solution to the equation x/3 + x/6 = 7/2

Mathematics

2 answers:

Tamiku [17]2 years ago

8 0

take l.c .m of 3 and 6 then

2x+x/6 = 7/2

3x = 7/2*3

x = 21/2/3

x = 21/2 * 1/3

x = 7/2

marta [7]2 years ago

4 0

Step-by-step explanation:

x/3+x/6=7/2

We simplify the equation to the form, which is simple to understand

x/3+x/6=7/2

Simplifying:

+ 0.333333333333x+x/6=7/2

Simplifying:

+ 0.333333333333x + 0.166666666667x=7/2

Simplifying:

+ 0.333333333333x + 0.166666666667x=+3.5

We move all terms containing x to the left and all other terms to the right.

+ 0.333333333333x + 0.166666666667x=+3.5

We simplify left and right side of the equation.

+ 0.5x=+3.5

We divide both sides of the equation by 0.5 to get x.

x=7

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Triss [41]

Answer:

option 1

Step-by-step explanation:

It's given in the question that

a (first term of an A.P.) = 14

d (common difference between terms of A.P.) = -3

So,

2nd term will be = a + d = 14 + (-3) = 11

3rd term = a + 2d = 14 + 2×(-3) = 8

4th term = a + 3d = 14 + 3×(-3) = 5

All these terms are matching with option 1. So, option 1 is the correct option

3 0

3 years ago

A random sample of 500 registered voters in Phoenix is asked if they favor the use of oxygenated fuels year-round to reduce air

Stells [14]

Answer:

a) 0.0853

b) 0.0000

Step-by-step explanation:

Parameters given stated that;

H₀ : p = 0.6

H₁ : p = 0.6, this explains the acceptance region as;

p° ≤ $\frac{315}{500}$ =0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)

a).

the probability of type I error if exactly 60% is calculated as :

∝ = P (Reject H₀ | H₀ is true)

= P (p°>0.63 | p=0.6)

where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p}{\sqrt{\frac{p(1-p)}{n}}} >\frac{0.63-p}{\sqrt{\frac{p(1-p)}{n}}} |p=0.6]$

= P $[\frac{p°-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} >\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} ]$

= P $[Z>\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500} } } ]$

= P [Z > 1.37]

= 1 - P [Z ≤ 1.37]

= 1 - Ф (1.37)

= 1 - 0.914657 ( from Cumulative Standard Normal Distribution Table)

≅ 0.0853

The probability of Type II error β is stated as:

β = P (Accept H₀ | H₁ is true)

= P [p° ≤ 0.63 | p = 0.75]

where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p} \sqrt{\frac{p(1-p)}{n} } }\leq \frac{0.63-p}{\sqrt{\frac{p(1-p)}{n} } } | p=0.75]$

= P $[\frac{p°-0.6} \sqrt{\frac{0.75(1-0.75)}{500} } }\leq \frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P $[Z\leq\frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P [Z ≤ -6.20]

= Ф (-6.20)

≅ 0.0000 (from Cumulative Standard Normal Distribution Table).

6 0

3 years ago

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aleksley [76]

Answer:

1.125 : 78

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6 0

3 years ago

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elixir [45]

Answer:

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3x = -3

x = -1

Step-by-step explanation:

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3 years ago

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kupik [55]

Answer:

50/b if I may say I think my answer is wrong

5 0

2 years ago

Read 2 more answers